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3 years ago

5. Sarah is standing 32.0 m away from Jason. If Sarah throws a snowball at a 45 degree

Physics

1 answer:

padilas [110]3 years ago

7 0

Answer:

Explanation:

If air resistance is ignored and assume UP and Toward Jason are the positive directions.

horizontal analysis

d = (vx₀)t

t = d/vx₀

horizontal analysis

0 = vy₀t + ½gt²

0 = vy₀(d/vx₀)+ ½g(d/vx₀)²

as vy₀ = v₀sin45 and vx₀ = v₀cos45 and are equal.

0 = d + ½g(d²/v₀²cos²45)

-d = ½g(d²/v₀²cos²45)

-dv₀² = ½g(d²/cos²45)

v₀² = -½g(d/cos²45)

v₀² = -½(-9.81(32.0/cos²45)

v₀² = 313.92

v₀ = 17.717787...

v₀ = 17.7 m/s

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Answer:

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Explanation:

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How many football fields (including the 10 yards in each end zone) would it take to make a mile?

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Answer:

Explanation:

1760 yd/mi / 120 yd/field = 14⅔ fields/mi

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3 years ago

A gas in a cylinder expands from a volume of 0.110 m³ to 0.320 m³. heat flows into the gas just rapidly enough to keep the press

Elden [556K]

80000 Joule is the change in the internal energy of the gas.

<h3>In Thermodynamics, work done by the gas during expansion at constant pressure:</h3>

ΔW = -pdV

ΔW = -pd (V₂ -V₁)

ΔW = - 1.65×10⁵ pa (0.320m³ - 0.110m³)

= - 0.35×10⁵ pa.m³

= - 35000 (N/m³)(m³)

= -35000 Nm

ΔW = -35000 Joule

Therefore, work done by the system = -35000 Joule

<h3>Change in the internal energy of the gas,</h3>

ΔV = ΔQ + ΔW

Given:

ΔQ = 1.15×10⁵ Joule

ΔW = -35000 Joule

ΔU = 1.15×10⁵ Joule - 35000 Joule

= 80000 Joule.

Therefore, the change in the internal energy of the gas= 80000 Joule.

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brainly.com/question/14265296

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2 years ago

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3 years ago

Ballon volume of 3200ml of xenon gas is at a gauge pressure of 122kPa and a temperature of 27c. What is the volume when the ball

N76 [4]

Given:

The initial volume of the gas, V₁=3200 ml=3.2×10⁻³ m³

The initial pressure of the gas, P₁=122 kPa

The initial temperature of the gas, T₁=27 °C=300 K

The final temperature, T₂=65 °C=338 K

The final pressure, P₂=112 kPa

To find:

The final volume of xenon gas.

Explanation:

From the combined gas law,

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

Where V₂ is the volume after it is heated.

On rearranging the above equation,

$V_2=\frac{T_2P_1V_1}{T_1P_2}$

On substituting the known values,

$\begin{gathered} V_2=\frac{338\times112\times10^3\times3.2\times10^{-3}}{300\times112\times10^3} \\ =3.61\text{ m}^3 \end{gathered}$

Final answer:

The volume of the balloon when it is heated is 3.61 m³

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