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Svet_ta [14]
3 years ago
15

A train car has a mass of 10,000 kg and is moving at +3.0 m/s. It strikes an identical train car that is at rest. The train cars

combine. What is the magnitude of the final velocity of the combined cars? 0 m/s 1.5 m/s 3.0 m/s 6.0 m/s
Physics
1 answer:
jolli1 [7]3 years ago
7 0

Answer:1.5

Explanation:

Edg

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The net force on an object moving with constant speed in circular motion is in which direction
ipn [44]

Answer:

the net force is the same direction as the acceleration

Explanation:

so toward the center of the circle about which the object is constantly moving.

7 0
2 years ago
20.0 moles, 1840 g, of a nonvolatile solute, C 3H 8O 3 is added to a flask with an unknown amount of water and stirred. The solu
Anastasy [175]

Answer:

0.144 kg of water

Explanation:

From Raoult's law,

Mole fraction of solvent = vapor pressure of solution ÷ vapor pressure of solvent = 423 mmHg ÷ 528.8 mmHg = 0.8

Let the moles of solvent (water) be y

Moles of solute (C3H8O3) = 2 mole

Total moles of solution = moles of solvent + moles of solute = (y + 2) mol

Mole fraction of solvent = moles of solvent/total moles of solution

0.8 = y/(y + 2)

y = 0.8(y + 2)

y = 0.8y + 1.6

y - 0.8y = 1.6

0.2y = 1.6

y = 1.6/0.2 = 8

Moles of solvent (water) = 8 mol

Mass of water = moles of water × MW = 8 mol × 18 g/mol = 144 g = 144/1000 = 0.144 kg

7 0
3 years ago
Suponga que usted pone en contacto 2 cuerpos, uno con carga +6 y otro con carga -8. ¿Con qué carga queda cada uno al final?
soldi70 [24.7K]
What is the question?
4 0
3 years ago
Is this right? Please help me
prohojiy [21]

Answer:

It would be C

Explanation:

The brain operates on two levels, one of them is unconscious.

6 0
2 years ago
Read 2 more answers
A 36-g ball at the end of a string is swung in a vertical circle with a radius of 19 cm. The tangential velocity is 200.0 cm/s.
STALIN [3.7K]

Answer:

0.758 N

Explanation:

mass of ball, = 36 g = 0.036 kg

radius, r = 19 cm = 0.19 m

tangential velocity, v = 200 cm / s = 2 m /s

The tension is the string is equal to the centripetal force acting on the ball.

The centripetal force acting on the ball is given by

T=\frac{mv^{2}}{r}

T=\frac{0.036 \times 2 \times 2}{0.19}

T = 0.758 N

Thus, the tension in the string is given by 0.758 N.

7 0
3 years ago
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