Answer:
y = 4x + 8
Step-by-step explanation:
1) Find slope:
y2-y1/x2-x1
12-8/1-0 = 4/1 = 4
Slope = 4
2) Plug in a point in point-slope form
y-y1=m(x-x1)
y-8=4(x-0) =
y-8=4x-0 -> add 8 to both sides
y=4x+8
 
        
             
        
        
        
Answer:
Step-by-step explanation:
4x+6+3x+8=28
combine like terms
7x+14=28
subtract 14
7x=14
divide
x=2
if you plug it in you get-
4(2)+6+3(2)+8=
8+6+6+8=12+16=28
thats how you can check. if you want me to explain more i can totally help
 
        
             
        
        
        
Approximately 2 gallons will be needed if each gallon of stain and  the project will cost be $73.96 if  each gallon costs $36.98
<h3>How to find the area of a triangle</h3>
The formula for calculating the area of a triangle is expressed as:
A = 0.5bh
where
base = 15feet
height = 20feet
Area of the deck = 20 * 15 * 0.5
Area of the deck is  150 square feet
Number of gallons needed  = 350/150 = 2.3
Hence approximately 2 gallons will be needed if each gallon of stain covers a maximum of 350 square feet.
Cost of the two gallons  = 36.98 *  2 
Cost of the two gallons  = $73.96
Hence the project will cost be $73.96 if  each gallon costs $36.98
Learn more on area of a triangle here: brainly.com/question/23945265
 
        
             
        
        
        
Answer:
The rate of change in surface area when r = 20 cm is 20,106.19 cm²/min.
Step-by-step explanation:
The area of a sphere is given by the following formula:

In which A is the area, measured in cm², and r is the radius, measured in cm.
Assume that the radius r of a sphere is expanding at a rate of 40 cm/min.
This means that 
Determine the rate of change in surface area when r = 20 cm.
This is  when
 when  . So
. So

Applying implicit differentiation.
We have two variables, A and r, so:



The rate of change in surface area when r = 20 cm is 20,106.19 cm²/min.
 
        
             
        
        
        
Answer:
Step-by-step explanation:
The two dump intervals have a greatest common factor (GCF) of 3, so their least common multiple (LCM) is ...
   (18)(21)/3 = 126 . . . . minutes
This period is 2 hours 6 minutes. The last time both dumped was 1:10, so the next time both will dump is ...
   1:10 +2:06 = 3:16 . . . P.M.
and the next time after that is ...
   3:16 +2:06 = 5:22 . . . P.M.