Answer:
11
Step-by-step explanation:
33÷11=3
22÷11=2
3 and 2 habe no common factors
Volume of the cone = 1/3π r^2 h
So, we are given that r = 9 and h = 12
plugging in all the known values
1/3 * (3.14) * 9 * 9 * 12
= 1017.36 cm³
or
≈1017.4 cm³
It is in the air 5.625 seconds.
Using the quadratic formula,

0 is when the ball is first launched, 5.625 is when it hits the ground again.
The answer is 54,550 more.
They are at the same position at 0.5 seconds because with respect to the ocean's surface, they are both 9 feet away.
Hope this helps!!