So i think that the question you are asking is the one of the exercise that says that the rope is very short and throws his bag also and you need to find the final speed of the bag tools. Well given the data we can use this next formulas to do this. First we are talking about conserve momentum: So we use a formula with the data like this:
<span>(135 + 13.0)kg * 1.50m/s = 135kg * V + 13.0kg * v </span>
<span>As we want V = 0; then </span>
<span>minimum v = 148kg * 1.50m/s / 13.0kg = 17.1 m/s
I hope is what you were looking for </span>
Explanation:
V = 3 cm/s = 0.03 m/s. BY THE FORmULA OF K.E. K.E = 1/2 mV^2. 300 =1/2 m (0.03)^2. m = 300 x 2/0.0009.
Because of the higher elevation. As much as we go away from earth by increasing altitude, there will occur lacoccuren. due to this, we need to breathe fast to get suffient oxygen by time at top of the mountain. We breathe faster at the top of a tall mountain due to a natural reflex. As we go higher up a mountain, the density of air and oxygen decreases, i.e. the amount of oxygen in the air decreases along with other gases. Therefore, to maintain the regular supply of oxygen, the body breathes faster. If we go too high without oxygen tanks, we could fall unconscious and die within 8 minutes due to oxygen deprivation.
Hope this helps! let me know if you need anything else!!
Answer:
a: increasing the positive charge of the positively charged object and increasing the negative charge of the negatively charged object
Explanation:
