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sladkih [1.3K]
3 years ago
13

What affects the vertical (y-component) of a projectile?

Physics
2 answers:
Shtirlitz [24]3 years ago
8 0
A. the force of gravity
34kurt3 years ago
5 0

Answer:

Gravity

EXPLANATION:

In the vertical or y direction, however, the projectile experiences the effect of gravity. As a result, the y component of the velocity  is not constant, but changes. The y component of the acceleration ay is the downward acceleration due to gravity.

<u><em>PLS MARK BRAINLIEST</em></u>

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Jim is driving a 2268-kg pickup truck at 22 m/s and releases his foot from the accelerator pedal. The car eventually stops due t
shutvik [7]

Answer:

610 meters.

Explanation:

Because Jim released the accelerator, the truck started to slow down, so the friction force will eventually stop the truck.

the kinetic energy of the truck just after Jim released the pedal is:

E_k=\frac{1}{2}*m*v^2\\E_k=\frac{1}{2}*2268*(22)^2=548856J

The work done by the friction force is given by:

W_f=F_s*d\\\\d=\frac{548856J}{900N}\\\\d=610m

6 0
3 years ago
The minimum stopping distance of a car moving at 20.5 mi/h is 11.6 m. Under the same conditions (so that the maximum braking for
pshichka [43]

Answer:

d = 69 .57 meter

Explanation:

First case

Speed of car ( v )  = 20.5 mi/h  = 9.164  M/S

distance ( d ) = 11.6 meter                                       ( m = mass of the car )

Work done = 0.5 m v²  = 0.5 * 9.164² * m J  = 41.99 m J

Force = ( workdone /distance ) = ( 41.99 m / 11.6 )   =  3.619 m N

Second case

v = 50.2 mi/h = 22.44135 m/s

d = ?

Work done = 0.5 * 22.44² * m J = 251.7768 * m J

Since the braking force remains the same .

3.619 m = ( 251.7768 m / d )

d = 69 .57 meter

7 0
3 years ago
The force on the spring is F0 and it stores elastic potential energy PEs0. If the spring displacement is tripled to 3x0, determi
Dimas [21]

Answer:

Explanation:

Let initial extension in the spring= x₀

Force on the spring = F₀

Let spring constant = k

Fo = k x₀

Fn = 3k x₀

Fn /Fo = 3

PEs0 ( ORIGINAL)  =1/2 k x₀²

PEsn ( NEW)  =1/2 k (3x₀)²

PEsn / PEs0 = 9

7 0
2 years ago
Describe difference between instantaneous velocity and average velocity
Alexxandr [17]

Answer:

The instantaneous velocity is the specific rate of change of position (or displacement) with respect to time at a single point (x,t) , while average velocity is the average rate of change of position (or displacement) with respect to time over an interval.Average velocity : Average velocity of a body is defined as the change in position or displacement (Δx) divided by time interval (Δt) in which that displacement occurs.

Instantaneous velocity : The instantaneous velocity of a body is the velocity of the body at any instant of time or at any point of its path .

velocity can be positive , negative or zero.

By studying speed and velocity we come to the result that at any time interval average speed of an object is equal or more than the average but instantaneous speed is equal to instantaneous velocity.

3 0
2 years ago
A car is traveling in uniform circular motion on a section of flat roadway whose radius is . The road is slippery, and the car i
Alona [7]

Answer:

The smallest radius will be four (4) times the initial radius

Explanation:

The car maintains a constant angular speed. According to Newton's Second Law F = m a

1. F_{r}=m*A_{n}

2. A_{n}=\frac{v^2}{R_{p}}

Replacing 2 in 1

3. F_{r}=m*\frac{v^2}{R_{p}}

Where:

Fr= Frictional force

Rp= Initial Radius

An= Centripetal Acceleration

M= Mass

V= Velocity

Also we have that:

4. F_{r}=\mu *W=\mu*m*g

μ= Coefficient of friction between the car and the surface

M= Mass

W= Weight

G= Gravity

r is cleared from equation 3

5. R_{p}=m*\frac{v^2}{F_{r}}

Replacing 4 in 5

6. R_{p}=m*\frac{v^2}{\mu*m*g}

Simplifying

7. R_{p}=\frac{v^2}{\mu*g}

Now we have a new velocity equal to twice the initial velocity, We replace it by 2v in equation 7

8. R_{n}=\frac{(2v)^2}{\mu*g}

Computing

9. R_{n}=\frac{4v^2}{\mu*g}

Replacing 5 in 9

R_{n}=4*R_{p}

8 0
3 years ago
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