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jeka94
3 years ago
6

A flywheel of diameter 1.2 m has a constant angular acceleration of 5.0 rad/s2. the tangential acceleration of a point on its ri

m is:
Physics
1 answer:
vodka [1.7K]3 years ago
5 0
We know that tangential acceleration is related with radius and angular acceleration according the following equation:  
at = r * aa  
where at is tangential acceleration (in m/s2), r is radius (in m) aa is angular acceleration (in rad/s2)  
So the radius is r = d/2 = 1.2/2 = 0.6 m  
Then at = 0.6 * 5 = 3 m/s2  
Tangential acceleration of a point on the flywheel rim is 3 m/s2
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