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monitta
2 years ago
12

What's the slope of (1, 4) and (0, 11) ?​

Mathematics
2 answers:
pogonyaev2 years ago
5 0

Answer: Slope = -7

Concept:

Here, we need to know the formula that helps to find the slope by two points.

The slope of a line is a number that describes both the direction and the steepness of the line.

Slope = Δy / Δx = (y₂ - y₁) / (x₂ - x₁)

Solve:

<u>Given information</u>

(x₁, y₁) = (1, 4)

(x₂, y₂) = (0, 11)

<u>Given expression</u>

Slope = (y₂ - y₁) / (x₂ - x₁)

<u>Substitute values into the expression</u>

Slope = (11 - 4) / (0 - 1)

<u>Simplify the values in the parentheses by subtraction</u>

Slope = (7) / (-1)

<u>Simplify by division</u>

\boxed{Slope=-7}

Hope this helps!! :)

Please let me know if you have any questions

Alisiya [41]2 years ago
4 0
-7 is the slope.

the slope formula is x2,y2-x1,y1
0-1=-1
11-4=7

the y goes on top of the x in the notation, so 7/-1 can be simplified to -7.

Hope this helps:)
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What is the result of a dilation of scale factor 3 centered at the origin of the line 2y + 3x=10?? PLEASE HELP PLEASEEEEEEEEE
maks197457 [2]

Given:

The equation of a line is:

2y+3x=10

The line is dilated by factor 3.

To find:

The result of dilation.

Solution:

The equation of a line is:

2y+3x=10

For x=0,

2y+3(0)=10

2y+0=10

y=\dfrac{10}{2}

y=5

For x=2,

2y+3(2)=10

2y+6=10

2y=10-6

2y=4

Divide both sides by 2.

y=\dfrac{4}{2}

y=2

The given line passes through the two points A(0,5) and B(2,2).

If the line dilated by factor 3 with origin as center of dilation, then

(x,y)\to (3x,3y)

Using this rule, we get

A(0,5)\to A'(3(0),3(5))

A(0,5)\to A'(0,15)

Similarly,

B(2,2)\to B'(3(2),3(2))

B(2,2)\to B'(6,6)

The dilated line passes through the points A'(0,15) and B'(6,6). So, the equation of dilated line is:

y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)

y-15=\dfrac{6-15}{6-0}(x-0)

y-15=\dfrac{-9}{6}(x)

y-15=\dfrac{-3}{2}x

Multiply both sides by 2.

2(y-15)=-3x

2y-30=-3x

2y+3x=30

Therefore, the equation of the line after the dilation is 2y+3x=30.

3 0
2 years ago
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