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3 years ago

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1 answer:

7 0

Perpendicular lines have negative reciprocals. This means that if you multiply the slopes of both lines, the product will be a -1.

In your given point-slope equation, the slope is 1/3. Therefore, the negative reciprocal of 1/3 must be -3.

Out of the given options:

y + 2 = -3(x — 4)
y = -3x - 5

are the linear equations that are perpendicular to y — 1 = 1/3(x + 2).

Therefore, the correct answers are Options 1 and 3.

Please mark my answers as the Brainliest if you find my explanations helpful :)

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What is the decay factor of the exponential function

worty [1.4K]

Answer:

a.)1/3

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

HELP A FELLA OUT Please

Vanyuwa [196]

I'll write "x" instead theta.

sin x + 1 = cos(2x)

formula: cos(2x) = 1 - 2sin²x

sin x + 1 = 1 - 2sin²x

2sin²x + sin x = 0

sin x (2sin x + 1) = 0

sin x = 0 or sin x = -1/2

x1 = πk and x2 = -π/6 + 2πk and

x3 = 5π/6 + 2πk

for domain 0≤x<2π :

x1 = 0 (for k=0 in x1)

x2 = π (for k=1 in x1

x3 = 11π/6 (for k=1 in x2)

x4 = 5π/6 (for k=0 in x3).

k is an integral.

8 0

3 years ago

44. Express each of these system specifications using predicates, quantifiers, and logical connectives. a) Every user has access

DENIUS [597]

Answer:

a. ∀x (User(x) → (∃y (Mailbox(y) ∧ Access(x, y))))

b. FileSystemLocked → ∀x Access(x, SystemMailbox)

c. ∀x ∀y ((Firewall(x) ∧ Diagnostic(x)) → (ProxyServer(y) → Diagnostic(y))

d. ∀x (ThroughputNormal ∧(ProxyServer(x)∧ ¬Diagnostic(x))) → (∃y Router(y)∧Functioning(y))

Step-by-step explanation:

Let the domain be users and mailboxes. Let User(x) be “x is a user”, let Mailbox(y) be “y is a mailbox”, and let Access(x, y) be “x has access to y”.

∀x (User(x) → (∃y (Mailbox(y) ∧ Access(x, y))))

(b)

Let the domain be people in the group. Let Access(x, y) be “x has access to y”. Let FileSystemLocked be the proposition “the file system is locked.” Let System Mailbox be the constant that is the system mailbox.

FileSystemLocked → ∀x Access(x, SystemMailbox)

(c)

Let the domain be all applications. Let Firewall(x) be “x is the firewall”, and let ProxyServer(x) be “x is the proxy server.” Let Diagnostic(x) be “x is in a diagnostic state”.

∀x ∀y ((Firewall(x) ∧ Diagnostic(x)) → (ProxyServer(y) → Diagnostic(y))

(d)

Let the domain be all applications and routers. Let Router(x) be “x is a router”, and let ProxyServer(x) be “x is the proxy server.” Let Diagnostic(x) be “x is in a diagnostic state”. Let ThroughputNormal be “the throughput is between 100kbps and 500 kbps”. Let Functioning(y) be “y is functioning normally”.

∀x (ThroughputNormal ∧(ProxyServer(x)∧ ¬Diagnostic(x))) → (∃y Router(y)∧Functioning(y))

4 0

3 years ago

How long is the rail? Round your answer to the nearest tenth.

ziro4ka [17]

Answer:

D. 15.7 yards

Step-by-step explanation:

The safety rail makes a curved side of a quarter circle.

The length of the safety rail = circumference of the curved part only of a quarter circle = ¼*2πr

Where,

radius = 10 yards

π = 3.14

Plug in the values

= ¼*2*3.14*10

= 15.7 yards.

✅The rail is 15.7 yards long.

8 0

3 years ago

Stephen uses 2/25 kilograms of tofu in each serving of his famous tofu dish. He has 1 1/10 kilograms of tofu. How many servings

larisa [96]

Answer: He has 1 1/10 kilograms of tofu.

Step-by-step explanation: We will have to divide the number of tofu required with the number of tofu own. Stephen uses 2/25 kilograms of tofu in each serving and he has 11/10 kilograms tofu.

7 0

3 years ago