Answer:
Explanation:
Given
Lowest four resonance frequencies are given with magnitude
50,100,150 and 200 Hz
The frequency of vibrating string is given by
where n=1,2,3 or ...n
L=Length of string
T=Tension
Mass per unit length
When string is clamped at mid-point
Effecting length becomes 
Thus new Frequency becomes
i.e. New frequency is double of old
so new lowest four resonant frequencies are 100,200,300 and 400 Hz
Answer:
50m
Explanation:
Given parameters:
Initial velocity = 20m/s
Acceleration = 4m/s²
Time = 10s
Unknown:
Distance traveled by the rocket = ?
Solution:
To solve this problem use the expression below;
v² = u² + 2as
v is the final velocity
u is the initial velocity
a is the acceleration
s is the distance
final velocity = 0
Insert the parameters and solve;
0² = 20² + 2 x 4 x s
-400 = 8s
s = 50m
Disregard the negative sign because distance cannot be negative.
No,because they may have more particles
Answer:
v = 87.57 m/s
Explanation:
Given,
The initial velocity of the car, u = 0
The final velocity of the car, v = 60 mi/hr
The time period of car, t = 8 s
= 0.00222 hr
The acceleration of the car is given by the formula,
a = (v -u) / t
= 60 / 0.00222
= 27027 mi/hr²
If the car has initial velocity, u = 50 mi/hr
The time period of the car, t = 5.0 s
= 0.00139 hr
Using first equations of motion
<em> v = u + at</em>
= 50 + (0.00139 x 27027)
= 87.57 mi/hr
Hence, the final velocity of the car, v = 87.57 mi/hr
Answer:
900 W.
Explanation:
Given that
Electric heater 1500 W
We know that power P given as
P= V I
So the total power of 120 V and 20 A circuit
P = 120 x 20
P= 2400 W
So the power new load P'
P'= Total system power(P)- Electric heater load
P ' = 2400 - 1500
P'= 900 W
So the answer is 900 W.
