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Setler [38]
3 years ago
8

A cow is walking at a velocity of 4 m/s and speeds up to 6 m/s in 5 seconds. Calculate the acceleration of the cow. Round your a

nswer to 2 decimal
places
Physics
1 answer:
siniylev [52]3 years ago
3 0

Answer:

0.4 m/s²

Explanation:

average acceleration = (final velocity - initial velocity)/ time elapsed

average acceleration = (6 - 4)/5

average acceleration = 2/5

average acceleration = 0.4 meters/seconds squared or 0.4m/s²

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Explain how the thermal energy of an isolated system changes with time if the mechanical energy of that system is constant.​
Naddika [18.5K]

Answer:

Thermal energy of an isolated system changes with time If the mechanical energy of that system is constant according to the first law of thermodynamics, which states that thermal energy of an isolated system can still change as long as the total energy of that system does not change.

Explanation:

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The global positioning system (GPS) uses electromagnetic waves sent between computer devices on Earth and satellites in space to
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Explanation:

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1. What is the wavelength of a sound wave with a frequency of 50 Hz, if the Speed of sound is 343 m/s.
marshall27 [118]

1.6.86

2.59.04

3.3

Thats the answer I think

7 0
3 years ago
A 7.36 g sample of copper is contaminated with a additional 0.51 g sample of zinc. Suppose an atomic mass measurement was perfor
yawa3891 [41]
The molar mass of the sample is equal to the summation of the molar mass of the elementas multiplied by the abundance of the elements by mole. In this case, copper has an abundance of 93.69 percent while zinc has 6.31 percent. In this case, the average molecular weight is 63.67 g/mol
7 0
3 years ago
A parallel-plate capacitor has square plates that are 8.00cm on each side and 4.20mm apart. The space between the plates is comp
Sergeu [11.5K]

Answer:

U=1.29\times 10^{-7}\ J

Explanation:

Given that

a= 8 cm (square)

A= a ² = 64 cm²

d= 4.2 mm

d₁= 2.1 mm  ,K₁= 4.7

d₂=2.1 mm  , K₂=2.6

We know that capacitance given as

C_1=\dfrac{K_1\varepsilon _oA}{d_1}

C_1=\dfrac{4.7\times 8.85\times 10^{-12}\times 64\times 10^{-4}}{2.1\times 10^{-3}}

C_1=1.26\times 10^{-10}\ F

C_2=\dfrac{K_2\varepsilon _oA}{d_2}

C_2=\dfrac{2.6\times 8.85\times 10^{-12}\times 64\times 10^{-4}}{2.1\times 10^{-3}}

C_2=0.701\times 10^{-10}\ F

Net capacitance

C=\dfrac{C_1C_2}{C_1+C_2}

C=\dfrac{1.26\times 10^{-10}\times 0.701\times 10^{-10}}{1.26\times 10^{-10}+0.701\times 10^{-10}}\ F

C=4.5\times 10^{-11}\ F

We know that stored energy given as

U=\dfrac{CV^2}{2}

V= 76 V

U=\dfrac{4.5\times 10^{-11}\times 76^2}{2}\ J

U=1.29\times 10^{-7}\ J

3 0
3 years ago
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