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2 years ago

When there is no air resistance, objects of different masses (1 points)

Physics

1 answer:

MA_775_DIABLO [31]2 years ago

3 0

Answer:

Fall at equal acceleration with similar displacements.

Explanation:

Objects under free fall with no air resistance, are falling under the sole influence of gravity. So, under that conditions, objects with different masses will fall with the same rate of acceleration

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A flat, rectangular coil consisting of 60 turns measures 23.0 cmcm by 34.0 cmcm . It is in a uniform, 1.40-TT, magnetic field, w

Travka [436]

Answer:

(a) ΔФ = -0.109W

(b) emf = 28.43V

Explanation:

(a) In order to calculate the magnetic flux you use the following formula:

$\Delta\Phi_B=\Phi-\Phi_o=BAcos(90\°)-BAcos(0\°)$ (1)

B: magnitude of the magnetic field = 1.40T

A: area of the rectangular coil = (0.23m)(0.34m)=0.078m^2

Where it has been taken into account that at the beginning the normal vector to the cross sectional area of the coil, and the magnetic field vector are parallel. When the coil is rotated the vectors are perpendicular.

Then, you obtain:

$\Delta\Phi_B=(1.40T)(0.078m^2)=-0.109W$

The change in the magnetic flux is -0.109 W

(b) During the rotation of the coil the emf induced is given by:

$emf=-N\frac{\Delta \Phi}{\Delta t}$ (2)

N: turns of the coil = 60

ΔФ: change in the magnetic flux = 0.109W

Δt: lapse time of the rotation = 0.230s

You replace the values of the parameters in the equation (2):

$emf=-(60)(\frac{-0.109W}{0.230s})=28.43V$

The induced emf is 28.43V

(c) The induced current in the coil is given by:

$I_{in}=\frac{emf}{R}$ (3)

R: resistance of the coil (it is necessary to have this value)

emf :induced emf = 28.43V

7 0

4 years ago

Please help only if you answer all 4

Oduvanchick [21]

Answer:

i think ice burg for 2nd page for penguin sorry if its wrong!

Explanation:

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3 years ago

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1. Define weight

bogdanovich [222]

Answer:

weight is the product of mass andgravitational acceleration expressed in newtons.
w=mg
w=mg ....w=50kg X 9.8m/s...w=490N

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3 years ago

Assuming 100% efficient energy conversion, how much water stored behind a 50cm high hydroelectric dam would be required to charg

7nadin3 [17]

Answer:

12.245m3

Explanation:

The electric energy is created by The potential energy substended by the specific volume of water in dam.

Electric energy is calculated as

E= Q× V

E is Energy, Q is charge and V is Voltage

Note that this energy has been given and is 60Joules

From conservation of energy it means;

M× g×h = 60

Where M is the mass of water.

g is acceleration of free fall due to gravity which is 9.8m/S2

h is the height of water flow.

From change of subject of formula for M; we have:

M = 60/ g × h

= 60/ 9.8 × 0.5

= 12.245kg

Now how much water required means the volume of water;

Note density = mass/volume

Therefore volume = mass/density

=12.245/1= 12.245m3

Note the density of water is 1kg/m3

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3 years ago

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3 years ago

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