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antoniya [11.8K]
3 years ago
7

A 10 kg brick and a 1 kg book are dropped in a vacuum. The force of gravity on the 10 kg brick is what?

Physics
2 answers:
Nadya [2.5K]3 years ago
7 0
<span>10 times as much. Since F=m*a, and a is constant, the only thing that affects force is the mass.

In response to the below answer, the acceleration due to gravity does not change. The force due to gravity definitely DOES change depending on the mass of the object. Since the force is what the problem asks for, the answer is 10</span>
LuckyWell [14K]3 years ago
3 0
If this is happening on Earth, then the force of gravity between the Earth and the brick is 98 Newtons. It doesn't matter whether the brick is falling, rising, dropped in a vacuum, in water, or into chicken soup, or what else is dropped near it. None of that has any effect on the gravitational force between the Earth and the brick.
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i believe atomic mass

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Peyote contains a psychotropic drug called __________.
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B. Mescaline

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A motorcycle daredevil plans to ride up a 2.0-m-high, 20° ramp, sail across a 10-m-wide pool filled with hungry crocodiles, and
il63 [147K]

Answer:

He becomes a croco-dile food

Explanation:

From the question we are told that

    The height is h = 2.0 m

      The angle is  \theta = 20^o

     The distance is  w = 10m

       The speed is  u = 11 m/s

       The coefficient of static friction is  \mu = 0.02

At equilibrium the forces acting on the motorcycle are mathematically represented as

        ma = mgsin \theta  + F_f

where  F_f is the frictional force mathematically represented as

            F_f =\mu F_x =\mu mgcos \theta

where F_x is the horizontal component of the force

substituting into the equation

            ma = mgsin \theta  + \mu mg cos \theta

            ma  =mg (sin \theta  + \mu cos \theta )

               making  a the subject of the formula

      a = g(sin \theta = \mu cos \theta )

          substituting values

      a = 9.8 (sin(20) + (0.02 ) cos (20 ))

        = 3.54 m/s^2

Applying " SOHCAHTOA" rule we mathematically evaluate that length of the ramp as  

             sin \theta = \frac{h}{l}

making l the subject

          l = \frac{h}{sin \theta }

substituting values

        l = \frac{2}{sin (20)}

           l = 5.85m

Apply Newton equation of motion we can mathematically evaluate the  final velocity at the end of the ramp  as

      v^2 =u^2 + 2 (-a)l

  The negative a means it is moving against gravity

      substituting values

      v^2 = (11)^2 - 2(3.54) (5.85)

           v= \sqrt{79.582}

              = 8.92m/s

The initial velocity at the beginning of the pool (end of ramp) is composed of two component which is

    Initial velocity along the x-axis which is mathematically evaluated as

          v_x = vcos 20^o

       substituting values

         v_x = 8.92 * cos (20)

              = 8.38 m/s

Initial velocity along the y-axis which is mathematically evaluated as

             v_y = vsin\theta

      substituting values

             v_y = 8.90 sin (20)

                  = 3.05 m/s

Now the motion through the pool in the vertical direction can mathematically modeled as

        y = y_o +  u_yt + \frac{1}{2} a_y t^2

where y_o is the initial height,

         u_y is the initial velocity in the y-axis

    a_y  is the  initial  acceleration in the y axis  with a constant value of (g = 9.8 m/s^2)

at the y= 0 which is when the height above ground is zero

      Substituting values

              0 = 2 + (3.05)t - 0.5 (9.8)t^2

The negative sign is because the acceleration is moving against the motion

                 -(4.9)t^2 + (2.79)t + 2m = 0

   Solving using quadratic formula

              \frac{-b \pm \sqrt{b^2 -4ac} }{2a}

substituting values

             \frac{-3.05 \pm \sqrt{(3.05)^2 - 4(-4.9) * 2} }{2 *( -4.9)}

                t = \frac{-3.05 + 6.9}{-9.8}   \ or t = \frac{-3.05 - 6.9}{-9.8}

                t = -0.39s  \ or  \ t = 1.02s

since in this case time cannot be negative

             t = 1.02s

At this time the position the  motorcycle along the x-axis is mathematically evaluated as

              x = u_x t

               x  =8.38 *1.02

                   x =8.54m

So from this value we can see that the motorcycle would not cross the pool as the position is less that the length of  the pool

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Why a steel ship becomes magnetized as it is constructed?
Tpy6a [65]
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ship is magnetized because <u></u>it has a superstructure,, during welding of ship enormous amount of current is passed through it and also it goes on and on path through the whole structure which aggregates the current up to thousands of amperes  ,,,
as a result this current re aline all the molecules because of which they become a little magnetic and make the entire steel ship magnetic :)</em>
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A point on a string undergoes simple harmonic motion as a sinusoidal wave passes. When a sinusoidal wave with speed 24 m/s, wave
Anit [1.1K]

Answer:

5.03 m/s

Explanation:

Give

Speed = v = 24m/s

Wavelength = λ = 30cm = 0.3m

Amplitude = A = 1.0cm = 0.01m

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at any time t is given by the following formula

v = ωA cos ωt

The value is the Maximum when cosωt.

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n = v/ λ = 24 /0.3 = 80

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Maximum velocity of the particle is

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