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IrinaVladis [17]

2 years ago

10

How do I Solve 16x - 37<10x-17

1 answer:

zlopas [31]2 years ago

3 0

Answer:

x= $\frac{10}{3}$

Step-by-step explanation:

I d k

I hope this helps

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Which of the segments below is a secant?

mamaluj [8]

b) HJ

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5 0

3 years ago

Read 2 more answers

Solve for linear inequality of x - 1 ≥ 4 + x

defon

$\huge\bf{ANSWER:}$

$\huge\mathrm{No\:solution.}\checkmark$

$\huge\bf{SOLUTION}:$

Hey there, hope you are having a wonderful day! :)

Let's solve this inequality.

First of all, let's move all the numbers to the right, using the $\bf{\underline{opposite\:\:operation\:}$ :

$\longmapsto$ $\sf{x-1\geq 4+x$

$\longmapsto\sf{x\geq 4+x+1$

$\longmapsto\sf{x\geq x+5$

Now, let's move the variables to the left:

$\longmapsto\sf{x-x\geq 5$

$\longmapsto\sf{0\geq 5$

Now, as you can see, we ended up with a false statement. 0 is NOT greater than 5.

Thus, there are no values of x that make the inequality true, and the inequality has

$\bold{No\:solutions.}$

Hope you find it helpful.

Feel free to ask if you have any doubts.

$\bf{-MistySparkles^**^*$

8 0

2 years ago

What digit is in the Hundred Thousand Place? 645,892

ASHA 777 [7]

The digit 6 is in the Hundred Thousand Place.

3 0

3 years ago

Read 2 more answers

Whixh list of numbers is ordered from least to greatest?

Rzqust [24]

Answer:

B is the solution

Step-by-step explanation:

-6.53 is the furthest from 0

-6 1/4 is closer to 0

6.57 is positive and more than 0

6 3/4 is also positive and more than 6.57

8 0

1 year ago

Find the solutions of the quadratic equation 14x^2+9x+10=014x

Vesnalui [34]

Answer:

Option B. $x=-\frac{9}{28}(+/-)\frac{\sqrt{479}}{28}i$

Step-by-step explanation:

we know that

The formula to solve a quadratic equation of the form $ax^{2} +bx+c=0$ is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$14x^{2}+9x+10=0$

so

$a=14\\b=9\\c=10$

substitute in the formula

$x=\frac{-9(+/-)\sqrt{9^{2}-4(14)(10)}} {2(14)}$

$x=\frac{-9(+/-)\sqrt{-479}} {28}$

Remember that

$i=\sqrt{-1}$

substitute

$x=\frac{-9(+/-)\sqrt{479}i} {28}$

$x=-\frac{9}{28}(+/-)\frac{\sqrt{479}}{28}i$

5 0

3 years ago