Answer:
3.3557047 mL
Explanation:
The density can be found using the following formula:

Let's rearrange the formula to find the volume,
.




The volume can be found by dividing the mass by the density. The mass of the chloroform is 5 grams and the density is 1.49 grams per milliliter. Therefore,

Substitute the values into the formula.

Divide. When we divide, the grams, or g, in the numerator and denominator will cancel out.


The volume of 5 grams of chloroform is 3.3557047 milliliters
Answer:
2.25 g
Explanation:
The mass of the solid X must be the total mass (beaker + solid X) less than the mass of the beaker. Then:
mass of the solid X = 34.40 - 32.15
mass of the solid X = 2.25 g
The difference of 0.25 g must occur for several problems: an incorrect weight in the balance, the configuration of the balance, the solid can be hydrophilic and absorbs water, and others.
Yes, it has many natural acids. However, the biggest and most prominent acid is the organic acid, malic acid.
Answer:
the heat of formation of isopropyl alcohol is -317.82 kJ/mol
Explanation:
The heat of combustion of isopropyl alcohol is given as follows;
C₃H₇OH (l) +(9/2)O₂ → 3CO₂(g) + 4H₂O (g)
The heat of combustion of CO₂ and H₂O are given as follows
C (s) + O₂ (g) → CO₂(g) = −393.50 kJ
H₂ (g) + 1/2·O₂(g) → H₂O (l) = −285.83 kJ
Therefore we have
3CO₂(g) + 4H₂O (g) → C₃H₇OH (l) +(9/2)O₂ which we can write as
3C (s) + 3O₂ (g) → 3CO₂(g) = −393.50 kJ × 3 =
4H₂ (g) + 2·O₂(g) → 4H₂O (l) = −285.83 kJ × 4
3CO₂(g) + 4H₂O (g) → C₃H₇OH (l) +(9/2)O₂ = +2006 kJ/mol
-1180.5 - 1143.32 +2006 = -317.82 kJ/mol
Therefore, the heat of formation of isopropyl alcohol = -317.82 kJ/mol.
Answer:
The final volume of the sample of gas
= 0.000151 
Explanation:
Initial volume
= 200 ml = 0.0002
Initial temperature
= 296 K
Initial pressure
= 101.3 K pa
Final temperature
= 336 K
Final pressure
= K pa
Relation between P , V & T is given by

Put all the values in the above equation we get

= 0.000151 
This is the final volume of the sample of gas.