Answer:
CuSO4(aq)
Explanation:
The aqueous for of CuSO₄ is an electrolyte and it will conduct electricity.
CuSO₄ is an ionic substance and in solid state, it will not have the ability to conduct electricity.
- In aqueous form, it will contain free mobile ions which serves as carriers of electric current.
- In the solid state, the ions are arranged into a crystal lattice and will not conduct a current of electricity.
- The remaining given compounds will not conduct electricity as they are non-polar and do not have free mobile electrons.
Heat_1: Get the ice to 0 degrees
Convert 7 kg to grams
7 kg [1000 grams / 1 kg] = 7000 grams
Heat needed to get the the ice from - 9 to 0
deltat = 0 - -9 = 9 degrees
m = 7000 grams
c = 2.1 joules/gram
Heat_1 = m*c*deltat
Heat_1 = 7000 * 2.1 * 9
Heat_1 = 132,300 joules
Heat_2: Melt the ice.
There is no temperature change. The formula is 333 j/gram
Formula: H = mass * constant
H = 7000 g * 333 J / gram
H = 2331000 joules
Heat_3: Total amount of Joules needed.
2331000 + 132300 = 2 463 300 joules
Convert to Megajoules
2 463 300 joules * 1 megajoule / 1000000 = 2.63 megajoules.
The pH of an aqueous solution that has a concentration of 0.35 M NaF and pKa for HF = 3.14 is 3.6.
<h3>How to calculate pH?</h3>
The pH of a solution refers to the degree of acidity or alkalinity of the solution. It can be calculated using the Henderson-Hasselbalch Equation as follows:
pH = pka + log ([A-]/[HA])
Where;
- A- = conjugate base
- HA = weak acid
pH = pKa + log([F-]/[HF])
pH = 3.14 + log(1/0.35)
pH = 3.14 + 0.4559 = 3.595
Therefore, the pH of an aqueous solution that has a concentration of 0.35 M NaF and pKa for HF = 3.14 is 3.6.
Learn more about pH at: brainly.com/question/15289741
There is part of an amino acid molecule that is called the R group or side chain. The side chain of the amino acid called glycine is a single hydrogen atom. The side chain is what differs from amino acid to amino acid.
