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Sonbull [250]
3 years ago
8

Which of the following factors affects the pressure of an enclosed gas?

Physics
2 answers:
ahrayia [7]3 years ago
8 0

Answer:

D) all of the above

Explanation:

As per ideal gas equation we know that

PV = nRT

here we know

n = number of moles

R = ideal gas equation

T = temperature

V = volume of the gas

so if we rearrange the equation then we know

P = \frac{nRT}{V}

so pressure depends on all factors

Volume, Temperature and number of particles

melamori03 [73]3 years ago
5 0
It would be d all of the above

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In an "atom smasher," two particles collide head on at relativistic speeds. If the velocity of the first particle is 0.741c to t
USPshnik [31]

Answer:

W_x = 0.9156\ c

Explanation:

given,

velocity of particle 1 = 0.741 c to left

velocity of second particle = 0.543 c to right

relative velocity between the particle = ?

for the relative velocity calculation we have formula

W_x = \dfrac{|u_x - v_x|}{1-\dfrac{u_xv_x}{c^2}}

u_x = 0.543 c

v_x = - 0.741 c

W_x = \dfrac{0.543 c - (-0.741 c)}{1-\dfrac{(0.543 c)(-0.741 c)}{c^2}}

W_x = \dfrac{0.543 c +0.741 c)}{1+\dfrac{(0.543)(0.741)c^2}{c^2}}

W_x = \dfrac{1.284c}{1+0.402363}

W_x = 0.9156\ c

Relative velocity of the particle is W_x = 0.9156\ c

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3 years ago
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3 years ago
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98 POINTS, 5 simple questions!! HELP
lozanna [386]

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PE = mgh where m is mass, g is gravity accel: 9.8 n h is height

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3 years ago
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