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r-ruslan [8.4K]
3 years ago
15

Ammonia and oxygen react to form nitrogen monoxide and water, like this:

Chemistry
1 answer:
olchik [2.2K]3 years ago
6 0

4NH3+5O2 <=>4NO + 6H2O

Using the definition of Kp, we have
Kp=(Pno^4*Ph2o^6)/(Pnh3^4*Po2^5)
where Pno=partial pressure of NO, etc.

The numerical value for a given temperature can be evaluated when the actual partial pressures are known.
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How many grams of CO2 are used when 7 g of oxygen are produced
lara [203]
308 grams of co2 is used
4 0
2 years ago
A 1.800-g sample of solid phenol (C6H5OH(s)) was burned in a bomb calorimeter whose total heat capacity is 11.66 kJ/?C. The temp
vichka [17]

Answer:

The balanced chemical equation:

C_6H_5OH(s)+7O_2(g)\rightarrow 6CO_2(g)+3H_2O(g)

Heat of combustion per gram of phenol is 32.454 kJ/g

Heat of combustion per gram of phenol is 3,050 kJ/mol

Explanation:

C_6H_5OH(s)+7O_2(g)\rightarrow 6CO_2(g)+3H_2O(g)

Heat capacity of calorimeter = C = 11.66 kJ/°C

Initial temperature of the calorimeter = T_1= 21.36^oC

Final temperature of the calorimeter = T_2= 26.37^oC

Heat absorbed by calorimeter = Q

Q=C\times \Delta T

Heat released during reaction = Q'

Q' = -Q ( law of conservation of energy)

Energy released on combustion of 1.800 grams of phenol = Q' = -(58.4166 kJ)

Heat of combustion per gram of phenol:

\frac{Q'}{1.800 g}=\frac{-58.4166 kJ}{1.800 g}=32.454 kJ/g

Molar mass of phenol = 94 g/mol

Heat of combustion per gram of phenol:

\frac{Q'}{\frac{1.800 g}{94 g/mol}}=\frac{-58.4166 kJ\times 94 g/mol}{1.800 g}=3,050 kJ/mol

3 0
3 years ago
Which of the gases in air are compounds? Explain how you can tell.
Eduardwww [97]

Answer:

\huge \underline\bold\red{Answer}

The air in the atmosphere consists of nitrogen, oxygen, which is the life-sustaining substance for animals and humans, carbon dioxide, water vapour and small amounts of other elements (argon, neon, etc.). Higher in the atmosphere air also contains ozone, helium and hydrogen.

5 0
3 years ago
Read 2 more answers
Answer the following questions based on the reaction below: NaOH(aq) + KHP(s) --&gt; NaKP(aq)+H2O(I)
Natali [406]

Answer:

<u />

  • <u>a) 1.44g</u>

<u />

  • <u>b) 77.3%</u>

<u />

Explanation:

<u>1. Chemical balanced equation (given)</u>

       NaOH(aq)+ KHP(s)\rightarrow NaKP(aq)+H_2O(l)

<u>2. Mole ratio</u>

1molNaOH(aq):1molKHP(s)

This is, 1 mol of NaOH will reacts with 1 mol of KHP.

<u />

<u>3. Find the number of moles in 72.14 mL of the base</u>

    Molarity=\text{number of moles of solute}/\text{volume of solution in liters}

    \text{Volume of solution}=72.14mL=0.07214liters

     \text{Number of moles of NaOH}=0.0978M\times 0.07214liter=0.007055mol

<u>4. Find the number of grams of KHP that reacted</u>

The number of moles of KHP that reacted is equal to the number of moles of NaOH, 0.007055 mol

Convert moles to grams:

  • mass = number moles × molar mass = 0.007055mol × 204.23g/mol
  • mass = 1.4408 g.

You have to round to 3 significant figures: 1.44 g (because the molarity is given with 3 significant figures).

<u>5. Find the percentage of KHP in the sample</u>

The percentage is how much of the substance is in 100 parts of the sample.

The formula is:

  • % = (mass of substance / mass of sample) × 100

  • % = (1.4408g/ 1.864g) × 100 = 77.3%
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3 years ago
Which geoiogic feature is most likey to from a mid
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