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Hoochie [10]
3 years ago
14

When light bounces off a rough surface, in different directions, what is this called?

Physics
1 answer:
vfiekz [6]3 years ago
7 0
This is called: diffuse reflection
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Find the unknown mass of the block 1 needed to balance the bar. Assume that the mass of the bar is negligible. Block 1 is locate
Natasha2012 [34]

Answer:

Incomplete question: The masses of the blocks m₂ = 1.5 kg and m₃ = 2 kg

Explanation:

Given data:

L₁ = length = 0.85 m

L₂ = 0.25 m

L₃ = 0.5 m

m₂ = 1.5 kg

m₃ = 2 kg

Question: Find the unknown mass of the block 1 needed to balance the bar, m₁ = ?

The torque is zero (intermediate point of the bar)

-m_{1} gL_{1} +m_{2} gL_{2} +m_{3} gL_{3} =0

Is negative because mass 1 is to the left of the coordinate system (see the diagram)

m_{1} =\frac{m_{2} gL_{2}+m_{3} gL_{3}  }{L_{1} } =\frac{(1.5*0.25)+(2*0.5)}{0.85} =1.6176kg

4 0
4 years ago
Which following options are examples of matter? A) light B) Molecules C) Feelings D) people
yaroslaw [1]
All except C, feelings are not physical.
6 0
4 years ago
Read 2 more answers
Find the polar coordinates corresponding to a point located at (−6.48, 12.58) in Cartesian coordinates
barxatty [35]

Answer:

Explanation:

r = √(-6.48² + 12.58²) = 14.1508586311... 14.15

θ = arctan(12.58 / -6.48) = 117.25314692... 117.25

(r, θ) = (14.15, 117.25)

5 0
3 years ago
Which increase the rate of soil formation? Check all that apply.
Alla [95]

Answer:

large grain sizes

more precipitation

warmer temperatures

Explanation:

6 0
3 years ago
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You are on the roof of a building, 46.0 m above the ground. Your friend, who is 1.80 m tall, is standing next to the building. W
Trava [24]

Answer:

29.448 ms^{-1}

Explanation:

first determine the distance from the top of the roof to the friends head.

Since he is 1.80 min height ,

distance =  46.0-1.80

              = 44.2 m

egg is dropped from rest means that its starting velocity is zero. It has to travel 44.2 m subjected to the gravitational acceleration

Applying  Motion equation

v^{2}=u^{2}+2as

where v= end velocity (speed)

           u=Starting velocity

           a= acceleration

           s= Distance

(Let gravitational acceleration assumed as 9.81 ms^{-2}

v^{2} =0^{2} +2*9.81*44.2\\v^{2} =867.204\\v=\sqrt{867.204}  \\v=29.448  ms^{-1}

7 0
3 years ago
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