The answer is D, because gems are usually not mettallic
Answer:
Volume of NCl3 is 3L
Explanation:
Avogadro states: All gases at the same volume under temperature and pressure constant have the same number of moles.
The chemical equation is:
3Cl2(g) + N2(g) → 2NCl3(g)
Where 3 moles of chlorine reacts with 1 mole of nitrogen to produce 2 moles of NCl3.
But using Avogadros law we can say:
3L of chlorine and 1L of nitrogen produce 2L of Nitrogen trichloride.
3L of chlorine and 1L of nitrogen: 4L (The stoichiometric mixture)
That means, volume of NCl3 produced is 3L
Hope this helps! 29.221385
Answer:
Unsaturated
Explanation:
In order to successfully answer this question, we need to think about the solubility of solutes in specific solvents, typically water.
- A solution is considered to be unsaturated if at a given temperature and volume of water we may still add more solute and it will dissolve;
- A solution is considered to be saturated if at a given temperature and volume of water we have a maximum amount of solute dissolved and trying to add more solute results in undissolved crystals that can be seen in the solution;
- A solution is considered to be oversaturated (or supersaturated) i at a given temperature and volume of water we exceeded the maximum amount of a solute that could possibly dissolve.
In this case, if we can continue to add more solute to a solution and the solute dissolves, we may state that we are still at a point in which we have an unsaturated solution.
The Zn that is 1.33 g is used at the start of the reaction where f is 520 ml and h2 collected over water is 28oc and the atmospheric pressure is 1.0 atm.
Given If 520 ml of H2 is gathered over Wate at 28 diploma Celsius and the atmospheric strain is 1 ATM if vapour strain of wate at 28 diploma celsius is 28.three mmhg then the quantity of zn in grams taken at begin of the response is.
We recognise that
h * 2 = PT - P * h * 20 = 1atm - 0.037atm
= 0.963 atm
1 * h * 2 = Ph * 2V / R * T
= 0.963 atm x 0.520 L / 0.0821 L atm/
molK * 301
= 0.02 mol h2
= 0.02molZn
So 0.02 mol Zn x 65.39 g/mol
= 1.33 g Zn
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