Q must be supplied = 119523.3~J
<h3>Further explanation </h3>
The law of conservation of energy can be applied to heat changes, i.e. the heat received/absorbed is the same as the heat released
Q in = Q out
Heat can be calculated using the formula:
Q = mc∆T
Q = heat, J
m = mass, g
c = specific heat, joules / g ° C
∆T = temperature difference, ° C / K
So from the question :
Q to the system(Q supplied) = Q water + Q steel vessel(Q gained)
![\tt Q~supplied=m.c\Delta T(water)+m.c\Delta T(vessel)\\\\Q~supplied=375\times 4.18\times (100-35)+532\times 0.51(100-35)\\\\Q~supplied=101887.5+17635.8=119523.3~J](https://tex.z-dn.net/?f=%5Ctt%20Q~supplied%3Dm.c%5CDelta%20T%28water%29%2Bm.c%5CDelta%20T%28vessel%29%5C%5C%5C%5CQ~supplied%3D375%5Ctimes%204.18%5Ctimes%20%28100-35%29%2B532%5Ctimes%200.51%28100-35%29%5C%5C%5C%5CQ~supplied%3D101887.5%2B17635.8%3D119523.3~J)