Answer:
Explanation:
first, you calculate the amount of O2 in moles:
98.0 ÷ 32 = 3.0625
second, the ratio if O2/C3H8 is 5 so you need to calculate O2 in moles with that:
3.0625 ÷ 5 = 0.6125
third, the amount of CO2 in moles also can be calculate by the ratio of C3H8/CO2 which is 3
0.6125 × 3 = 1.8375
then multiply CO2 in moles by its molar mass which is 44 g/mol
1.8375 × 44 = 80.85g
The answer is C: "<span>A body cell has 46 chromosomes; a sex cell has 23"</span>
8) 21.504 liters of gas
9) 122.5 g
10) 6.022*10^23
Explanation:
8)
1 mole= 22.4 liters
to calculate the volume of gas of 0.960 moles of CH4
22.4*0.960/1
= 21.504 liters of gas
9)
2.0 mole*18.02 g/ 1 mole
=122.5 g
10)
2.0 l * 1 mole/22.4 l
6.022*10^23
The answer to your equation is c
Answer: a) The concentration after 8.8min is 0.17 M
b) Time taken for the concentration of cyclopropane to decrease from 0.25M to 0.15M is 687 seconds.
Explanation:
Expression for rate law for first order kinetics is given by:
where,
k = rate constant
t = age of sample
a = let initial amount of the reactant
a - x = amount left after decay process
a) concentration after 8.8 min:
b) for concentration to decrease from 0.25M to 0.15M
