1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ikadub [295]
3 years ago
6

Determine the initial void ratio, the relative density and the unit weight (in pounds per cubic foot) of the specimens for each

sand.
Engineering
1 answer:
Elina [12.6K]3 years ago
5 0

The initial void ratio is the <em>parameter </em>which is used to show the structural foundations for each <em>specimen of sand </em>so that the method and speed of compression would be <em>measured</em>.

Relative density is the mass per unit volume of each specimen of sand which is <em>measured </em>and it has to do with the<em> relative ratio</em> of the density of the sand.

Unit weight is the the exact weight per cubic foot of the sand which is measured.

Please note that your question is incomplete so I gave you a general overview to help you better understand the concept

Read more here:

brainly.com/question/15220801

You might be interested in
Bars A and B have cross-sectional areas of 400 m2 and a modulus of elasticity of 200 GPa. A gap exists between bar A and the rig
NISA [10]

Answer:

axial stress in bar B = 25Mpa.

Deformation of bar A = 0.4mm.

Explanation:

PS: Kindly check the attached picture for the diagram showing the two bars that is to say the bar A and the bar B.

So, we are given the following data or information or parameters which we are going to use in solving this particular question or problem. Here they are;

The cross-sectional areas of Bars A and B =  400 mm2, the  modulus of elasticity of  bar A and bar B = 200 GPa, applied force = 10kN.

STEP ONE: The first step is to determine or calculate the axial stress in bar B. Therefore,

Axial stress in bar B = 10 × 10³ ÷ 400 × 10⁻⁶ = 25 Mpa.

STEP TWO: The second step here is to determine or calculate the deformation of bar A. Therefore,

The deformation of bar A = 20 × 10³ ×1.5 ÷ 400 × 10⁻⁶ × 200 × 10³ = 0.375 mm.

3 0
3 years ago
Consider a refrigerator that consumes 320 W of electric power when it is running. If the refrigerator runs only one quarter of t
Semenov [28]

Answer:

B. $5.18

Explanation:

Cost of electricity per kWh = $0.09

Power consumption of refrigerator = 320W = 320/1000 = 0.32kW

In a month (30 days) the refrigerator works 1/4 × 30 days = 7.5 days = 7.5 × 24 hours = 180 hours

Energy consumed in 180 hours = 0.32kW × 180h = 57.6kWh

Cost of electricity of 57.6kWh energy consumed by the refrigerator = 57.6 × $0.09 = $5.18

3 0
4 years ago
Read 2 more answers
Object has a mass of 0.5 kg and is 1.9 meters above the ground. What is PEg?
Ugo [173]

Answer:

Polyethylene glycol (PEG) is a biocompatible, synthetic, hydrophilic polyether compound that has many applications, mostly in the medical industry, but also in the chemical and industrial sectors.

Explanation:

6 0
2 years ago
A floor system has W24 x 55 sections spaced 8’-0"" o.c. supporting a floor dead load of 50 psf and a live load of 80 psf. Determ
galben [10]

Answer:

Load sup[port by beam is 1040 lb/ft

Explanation:

Given data:

dead load of floor is 50 psf

live load of floor is 80 psf

load per meter can be determined as

Load/mt length = load intensity × effective width

total load  = deal load + live load

                  = 50 + 80 = 130 psf

load /mt length =  130 × 8

                         = 1040 p/ft = 1.04 k /ft

hence load sup[port by beam is 1040 lb/ft

4 0
4 years ago
E total kinetic energy of a 2500 lbm car when it is moving at 80 mph (in BTU)?
Galina-37 [17]

Answer:

KE= 687.21 BTU

Explanation:

Given that

Mass of car = 2500 lbm

We know that 1 lb=0.45 kg

So the mass of car  m =1133.98 kg

Velocity of car= 80 mph

We know that 1 mph =0.44 m/s

So velocity of car = 35.76 m/s

As we know that kinetic energy (KE) is given as follows

KE=\dfrac{1}{2}mv^2

Now by putting the values

KE=\dfrac{1}{2}\times 1133.98\times 35.76^2

KE=725.05 KJ

We know that   1 KJ = 0.94 BTU

So  KE= 687.21 BTU

3 0
4 years ago
Other questions:
  • Air modeled as an ideal gas enters a turbine operating at steady state at 1040 K, 278 kPa and exits at 120 kPa. The mass flow ra
    12·1 answer
  • Modify the one-dimensional continuity equation to include rainfall over the free surface
    15·1 answer
  • Name the seven physical qualities for which standards have been developed.
    7·1 answer
  • Name one challenge for engineering managers wanting to implement the concurrent engineering concept
    12·1 answer
  • Convert the following pairs of voltage and current waveforms to phasor form. Each pair of waveforms corresponds to an unknown el
    5·1 answer
  • Ben is an aeronautical engineer who helps build rockets. What talent might help ben in his career?
    14·1 answer
  • Hey, Whos sooo bored right now? Also who is going to get a pet soon? I find the perfect pet for you for free!
    14·1 answer
  • Act as food engineers or biomedical engineers and write a short paragraph explaining why they need to know about mixtures and so
    11·1 answer
  • Pls answer and I will give a like!
    8·1 answer
  • Hich of the following would be a strong incentive for people interested in construction to choose being an electrician as a care
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!