Answer:
Part a: The potential at point 3 and point 6 are V and 0 respectively.
Part b: The charges Q1, Q2 and Q3 are CV, 2CV and 3CV respectively.
Part c: The net charge is 6CV.
Part d: The equivalent capacitance is 6C
Explanation:
As the question is not given here ,the complete question is found online and is attached herewith.
Part a:
V1 = V, V3 = V1 = V
and, V6 = V1-V = 0
The potential at point 3 and point 6 are V and 0 respectively
Part b
Q1 =CV = Q,
Q2 = 2C *V = 2Q
Q3 = 3 C*V = 3Q
So the charges Q1, Q2 and Q3 are CV, 2CV and 3CV respectively.
Part c
Total charge of the system,
Q_net =Q1+Q2+Q3= (1+2+3) CV = 6 CV
So the net charge is 6CV.
Part d:
Equivalent Capacitance = Net charge / Voltage
Eq. C = 6CV/V = 6C
So the equivalent capacitance is 6C
