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Karo-lina-s [1.5K]
3 years ago
5

Two stones resembling diamonds are suspected of being fakes. To determine if the stones might be real, the mass and volume of ea

ch are measured. Both stones have the same volume, 0.15 cm3. However, stone A has a mass of 0.52 g, and stone B has a mass of 0.42 g. If diamond has a density of 3.5 g/cm3, could either of the stones be real diamonds?
Physics
1 answer:
dimaraw [331]3 years ago
6 0

Answer:

stone A is diamond.

Explanation:

given,

Volume of the two stone =  0.15 cm³

Mass of stone A = 0.52 g

Mass of stone B = 0.42 g

Density of the diamond =  3.5 g/cm³

So, to find which stone is gold we have to calculate the density of both the stone.

We know,

density\density = \dfrac{mass}{volume}

density of stone A

\rho_A = \dfrac{0.52}{0.15}

\rho_A = 3.467\ g/cm^3

density of stone B.

\rho_B = \dfrac{0.42}{0.15}

\rho_B = 2.8\ g/cm^3

Hence, the density of the stone A is the equal to Diamond then stone A is diamond.

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The answer for the following answer is answered below.

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Explanation:

Frequency (f):

The number of  waves that pass a fixed place in a given amount of time.

The SI unit of frequency is Hertz (Hz)

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The SI unit of time period is seconds (s)

Given:

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We know;

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from the formula;

  T = \frac{1}{f}

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  T = 0.01 seconds

<u><em>Therefore the time period of the wave is 0.01 seconds.</em></u>

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