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Alexus [3.1K]
3 years ago
6

A car is moving in uniform circular motion. If the cars speed were to double to keep the car moving with the same radius the acc

eleration would?
A- Increase by a factor of 2
B- Increase by a factor of 4
C- Decrease by a factor of 2
D- Decrease by a factor of 4
Physics
1 answer:
Stells [14]3 years ago
5 0

Answer:

<em>The centripetal acceleration would increase by a factor of 4</em>

<em>Correct choice: B.</em>

Explanation:

<u>Circular Motion</u>

The circular motion is described when an object rotates about a fixed point called center. The distance from the object to the center is the radius. There are other magnitudes in the circular motion like the angular speed, tangent speed, and centripetal acceleration. The formulas are:

v_t=w\ r

\displaystyle a_c=\frac{v_t^2}{r}

If the speed is doubled and the radius is the same, then

\displaystyle a_c=\frac{(2v_t)^2}{r}

\displaystyle a_c=4\frac{v_t^2}{r}

The centripetal acceleration would increase by a factor of 4

Correct choice: B.

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Consider a spherical planet of uniform density rho. The distance from the planet's center to its surface (i.e., the planet's rad
alisha [4.7K]

Answer:

a) g(r) = 4\pi \cdot G \cdot \rho\cdot r, b) g = 4\pi \cdot G \cdot \rho\cdot r_{P}

Explanation:

a) The acceleration due to gravity inside the planet is:

dg = G\cdot \frac{\rho \cdot dV}{r^{2}}

dg = G\cdot \frac{\rho \cdot dV}{r^{2}}

dg = G\cdot \frac{4\pi\cdot \rho \cdot r^{2}\,dr}{r^{2}}

dg = 4\pi\cdot G\cdot \rho \,dr

g(r) = 4\pi \cdot G \cdot \rho\cdot r

b) The acceleration at the surface of the planet is:

g = 4\pi \cdot G \cdot \rho\cdot r_{P}

5 0
3 years ago
An engine has an energy input of 125 J, and 35 J of that energy is transformed into useful energy. What is the efficiency of the
xeze [42]

The efficiency of the engine at the given useful energy and input energy is 28%.

The given parameters:

  • <em>Input energy of the engine, = 125 J</em>
  • <em>Useful energy of the engine, 35 J</em>

The efficiency of the engine is defined as the ratio of the output energy (useful energy) to the input energy and it is calculated as follows;

efficiency\ = \frac{0ut put \ energy}{1nput \ energy} \times \ 100\%\\\\efficiency\ = \frac{35}{125} \times 100\%\\\\efficiency\ = 28 \ \%

Thus, the efficiency of the engine at the given useful energy and input energy is 28%.

Learn more about efficiency of engine here: brainly.com/question/6751595

7 0
2 years ago
The speed of water at the tap of lower storey is more than that in the upper storey​
nadezda [96]

Answer:

Pressure of liquid in container is given by, P= height × density × acceleration of gravity.

At the lower storey, the height of the liquid from the open end is great, since height is directly proportional to pressure, the pressure exerted by liquid is maximum hence increase in velocity of flow.

Unlike the upper storey where the height of water is less hence the pressure exerted by the liquid is minimum which decreases the velocity / speed of liquid flow

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3 years ago
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tatuchka [14]

Answer:

D.

Explanation:

This is the essence of “correlation does not imply causation”. When there is a common cause between two variables, then they will be correlated. This is part of the reasoning behind the less-known phrase, “ There is no correlation without causation ”.

5 0
4 years ago
If you change the mass of a moving object, you change its _______.
Paul [167]
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6 0
3 years ago
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