We have as a reagent a salt, lead nitrate (Pb(NO3)2), and an unknown solution that gives us as a product lead chloride (PbCl2). That is, the solution must contain chlorine.
If a chlorine solution is used we will have the following reaction:
![Pb(NO_{3)2}+2Cl^-\rightarrow PbCl_2+2NO^-_3](https://tex.z-dn.net/?f=Pb%28NO_%7B3%292%7D%2B2Cl%5E-%5Crightarrow%20PbCl_2%2B2NO%5E-_3)
So, with a chlorine solution, we will have a white precipitate of lead chloride.
Answer:
A. 2.4 x 10¹⁴ J
Explanation:
m (mass) = 2.7 x 10⁻³ kg
c = 3.0 x 10⁸ m/s
Plug these numbers into the equation E=mc²
E=mc²
E= (2.7 x 10⁻³)(3.0 x 10⁸)²
E= 2.43 x 10¹⁴
So, the answer is A. 2.4 x 10¹⁴ J.