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ankoles [38]
3 years ago
12

Is Sc2S3 polar or non polar or ionic

Chemistry
1 answer:
sammy [17]3 years ago
6 0

Answer: Ionic

Explanation:

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(b) A compound X contains carbon, hydrogen and oxygen only
faust18 [17]

Answer:

C2H4O

Explanation:

C H O

54.54/12 9.09/1 36.37/16

4.545 9.09 2.27

4.545/2.27 9.09/2.27 2.27/2.27

2.00 4.00 1

Empirical formula is C2H4O

3 0
3 years ago
Which of the following is a factor in natural selection?
Vera_Pavlovna [14]

Answer:

D.

Explanation:

Although all of these answers are similar, it seems that all three are the answer. I am sorry if the answer ends up being B but I'm pretty sure the answer is D. Charles Darwin's evolution theory "evolved", get it, from the natural selection theory. The theory is described as "the process whereby organisms better adapted to their environment tend to survive and produce more offspring." However, some factors that effect natural selection are competition, selection and variation. I believe all three fit the answer and therefore I believe answer D is correct.

5 0
3 years ago
Read 2 more answers
Lonization energy is the
Tamiku [17]
Arrow on the table below draw an
3 0
2 years ago
Which of the following situations indicates an alpha emission?
Angelina_Jolie [31]
Your answer would be C. Alpha decay involves the ejection of 2 protons and 2 neutrons from the nucleus for a total of 4 amu lost. This form of decay is most common in heavy elements.
4 0
2 years ago
A mixture of MgCl2 and NaCl has an initial mass of 0.4015 g. Excess AgNO3(aq) was added and 1.032 g of precipitate, AgCl(s), was
zlopas [31]

Answer:

8.909*10^-4 moles

Explanation:

The mixture contains MgCl_{2} and NaCl with a total mass of 0.4015 g. The mass of precipitate AgCl(aq) is 1.032 g and it has a molar mass of 143.32 g/mol. Therefore, the moles of the precipitate is:

n = 1.032/143.32 = 7.2007*10^-3 moles

Molar mass of NaCl = 58.44 g/mol and the molar mass of MgCl_{2} is 95.21 g/mol. Let the mass (g) of MgCl_{2}  in the original mixture be 'x'. Thus:

7.2007*10^-3 = (0.4015-x)/58.44 + 2x/95.21

(7.2007*10^-3)*58.44*95.21 = 95.21(0.4015-x) + 2x(58.44)

40.06505 = 38.227 -95.21x + 116.88x

40.06505 - 38.227 = -95.21x + 116.88x

1.83805 = 21.67x

x = 1.83805/21.67 = 0.0848 g

moles of MgCl_{2} = 0.0848g/95.21 g/mol = 8.909*10^-4 moles

4 0
3 years ago
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