Balanced equation will be as follows
2NaOH + H2SO4=Na2SO4 + 2H2O
from MaVa/MbVb=Na/Nb where Ma is molarity of acid=?
Va is volume of acid=25.0 mL
Mb is molarity of base= 0.05 M
Vb is volume of base=18.3 mL
Nb number of moles of base= 2
Na is number of moles of acid =1
Ma*25 mL / 18.3mL*0.05M = 1/2
Ma=18.3*0.05M / 50 = 0.0183M
The molarity of sulphuric acid = 0.0183M
Answer:
Osmolarity of solution of KCI = 0.40 osmol
Explanation:
Given:
KCL ⇒ K⁺ + Cl⁻
Find:
Osmolarity of solution of KCI
When M = 0.20 M
Computation:
1 mole of KCL = 2 osmol
1 M of KCl = 2 Osmolarity
So,
Osmolarity of solution of KCI = 2 × 0.20
Osmolarity of solution of KCI = 0.40 osmol
The correct answer is the octet rule.
Octet rule states that atoms tend to bond in order to have 8 electrons in their outer most electron orbit achieve stable configurations of noble gases.
When atoms form covalent bonds, they achieve the goal of having 8 electrons by sharing the electrons.
In ionic bond, atom either gain or lose an electron and form ions that have the stable configuration of 8 valence electrons.
Not all atoms follow the octet rule and there are many exceptions and variations.
You are correct! this molecule is an ether, specifically diethyl ether.
