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a) 3 molecule of carbon dioxide (CO2) - 3 carbon atoms
b) 6 molecule of 3 - PGA - 18 carbon atoms ( 3 cabon atoms in 1 3 PGA molecule)
c) 6 molecule og G3P - 18 carbon atom ( 3 carbon atoms in G3P molecule )
d) 5 molecules of G3P - 15 carbon atom
e) 3 molecule of R5P - 15 carbon atoms ( 5 carbon atom of R5P olecule )
f) 3 molecule of RuBP - 15 carbon atoms ( r carbon atom of RuBp molecule )
Answer:
30.11 × 10²³ atoms
Explanation:
Given data:
Number of moles of gold = 5 mol
Number of atoms = ?
Solution:
The given problem will solve by using Avogadro number.
It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance. The number 6.022 × 10²³ is called Avogadro number.
1 mole = 6.022 × 10²³ atoms
5 mol × 6.022 × 10²³ atoms /1 mol
30.11 × 10²³ atoms
Fe is the limiting reactant.
The balanced chemical equation between iron and oxygen to produce iron (III) oxide is
4Fe(s) + 302(g) - ---> 2Fe2O3(s)
Mass of Fe = 227.8 g
Moles of Fe = 227.8gFe*Imol Fe/55.85g Fe = 4.079mol Fe
Mass of oxygen = 128 g
Moles of O2 = 128g02 * 1molo/32g02 = 4molO2
Calculating the limiting reactant: The reactant that produces the least amount of product will be the limiting reactant.
Mass of iron (III) oxide produced from Iron = 4.079mol Fe*2molFe2O3/4molFe*159.69g Fe2O3/1 mol Fe2O3 = 325.7gFe2O3
Mass of iron (III) oxide produced from oxygen = 4molO2 *2mol Fe2O3/3molO2*159.69gFe2O3/1mol Fe2O3 = 425.84gFe2O3
Iron (Fe) produces the least amount of the product iron (III) oxide. So, Fe is the limiting reactant.
Learn more about Limiting reagent here:
brainly.com/question/14225536
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