3 years ago

Which carboxylic acid is used to prepare the ester shown?

Chemistry

1 answer:

valentinak56 [21]3 years ago

3 0

Answer:

Explanation:

The general equation for the reaction of a carboxylic acid with an alkanol to form an ester is shown below;

RCOOH + ROH ------> RCOOR + H2O

Hence; the reactant carboxylic acid can only be the compound (CH3)2-CH-CH2-COOH in accordance with the general reaction equation shown above.

Hence the reaction is;

(CH3)2-CH-CH2-COOH + CH3-CH2OH -------> CH3CH2 OCO-CH2-CH-(CH3)2

You might be interested in

Given that the density of water is 1.00 g/mL, the density of toluene is 0.867 g/mL, and the density of chloroform is 1.48 g/mL,

12345 [234]

Answer:
Top-Toluene
Middle-Water
Bottom-Chloroform

Explication:
Chloroform is on the bottom layer because it is the densest liquid.
Toluene is on the top because it is the least dense.
Water is between the two because it’s density is between chloroform and toluene.

4 0

3 years ago

Dalton hypothesized that atoms are indivisible and that all atoms of an element are identical. It is now known that _____.

34kurt

Dalton hypothesized that atoms are indivisible and that all atoms of an element are identical. It is now known that <span>atoms are divisible. The answer is letter C</span>

8 0

3 years ago

Read 2 more answers

The expected value for a chemical equation is 47g of water, after an experiment you find that you have 2.58 moles of water. What

strojnjashka [21]

<h3><u>Answer</u>;</h3>

Actual yield = 46.44 g

<h3><u>Explanation;</u></h3>

1 mole of water = 18 g/mol

Therefore;

The experimental yield = 2.58 moles

equivalent to ; 2.58 × 18 = 46.44 g