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Burka [1]
3 years ago
9

water is a molecule of oxygen and hydrogen. The bonds that hold water molecules together are due to shared what

Physics
1 answer:
Olenka [21]3 years ago
8 0
The bonds that hold water molecules together are due to shared electrons. Hope I helped!
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A stone is thrown horizontally with an initial speed of 10 m/s from the edge of a cliff. A stopwatch measures the stone's trajec
olga2289 [7]

Answer:

The height of the cliff is 90.60 meters.

Explanation:

It is given that,

Initial horizontal speed of the stone, u = 10 m/s

Initial vertical speed of the stone, u' = 0 (as there is no motion in vertical direction)

The time taken by the stone from the top of the cliff to the bottom to be 4.3 s, t = 4.3 s

Let h is the height of the cliff. Using the second equation of motion in vertical direction to find it. It is given by :

h=u't+\dfrac{1}{2}gt^2

h=\dfrac{1}{2}gt^2

h=\dfrac{1}{2}\times 9.8\times (4.3)^2

h = 90.60 meters

So, the height of the cliff is 90.60 meters. Hence, this is the required solution.

5 0
3 years ago
Classyfying— what is the name of the force you exert on a sponge when you squeeze it?
Kruka [31]
Its called compression
5 0
3 years ago
Read 2 more answers
Which of the following is a zone found in the open ocean
Svetlanka [38]
What are your answer choices?

5 0
3 years ago
Read 2 more answers
Who wanna be my friend im a girl and im 13 and im lightskin and black curly hair
Dafna11 [192]

Answer:

Would love to be your friend m'lady.

Explanation:

8 0
3 years ago
Red laser light from a He-Ne laser (λ = 632.8 nm) creates a second-order fringe at 53.2° after passing through the grating. What
Svetlanka [38]

Explanation:

It is given that,

Wavelength of red laser light, \lambda=632.8\ nm=632.8\times 10^{-9}\ m

The second order fringe is formed at an angle of, \theta=53.2^{\circ}

For diffraction grating,

d\ sin\theta=n\lambda

d=\dfrac{n\lambda}{sin\theta}, n = 2

d=\dfrac{2\times 632.8\times 10^{-9}}{sin(53.2)}

d=1.58\times 10^{-6}\ m

The wavelength λ of light that creates a first-order fringe at 22 is given by :

\lambda=d\ sin\theta

\lambda=1.58\times 10^{-6}\ sin(22)

\lambda=5.91\times 10^{-7}\ m

\lambda=591\ nm

Hence, this is the required solution.

6 0
3 years ago
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