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3 years ago

1. Who explained the motions of the planets of the solar system at the same

Physics

1 answer:

Mrac [35]3 years ago

6 0

Issac Newton

He explained both the gravity of the earth and the motion of the planets with the solar system, which is also due to gravity, with his well known third law of motion.

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The displacement y is expressed as a function of x and t in terms of the wave numberk and the angular frequency. Write the equiv

Phoenix [80]

Explanation:

The displacement equation is given by :

(a) $y=A\ sin(\omega t\pm kx)$

Since, $\omega=2\pi f$

$\lambda=\dfrac{2\pi}{k}$

$y=A\ sin(2\pi f t\pm kx)$

$y=A\ sin(\dfrac{2\pi vt}{2\pi /k}\pm kx)$

$y=A\ sin(kvt+kx)$

$y=A\ sink(vt+x)$

The above equation is in terms of k and v.

(b) $y=A\ sin(\omega t\pm kx)$

$y=A\ sin(2\pi \dfrac{v}{\lambda}t\pm\dfrac{2\pi}{\lambda}x)$

$y=Asin\dfrac{2\pi}{\lambda}(vt\pm x)$

$y=A\ sin(2\pi f t\pm \dfrac{2\pi}{\lambda} x)$

$y=A\ sin\ 2\pi (ft\pm \dfrac{x}{\lambda})$

(d) $y=A\ sin(\omega t\pm kx)$

$y=A\ sin(2\pi ft+\dfrac{2\pi}{\lambda}x)$

$y=A\ sin(2\pi ft+\dfrac{2\pi}{v/f}x)$

$y=A\ sin\ 2\pi f(t+\dfrac{x}{v})$

Where

k is the propagation constant

v is the speed of wave

f is the frequency of a wave

$\lambda$ is the wavelength

Hence, this is the required solution.

3 0

3 years ago

Two blocks with a mass of 2 kg collide in an elastic collision. The initial velocity of Block 1 is 10 m/s. Block 2 is traveling

pentagon [3]

Answer:

p = 20 kg•m/s

KE = 100 J

Explanation:

In an elastic collision of identical masses, the two masses will exchange momentums. Therefore Block 1 initially moving at 10 m/s will be moving at 2 m/s, and Block 2 will go from 2 m/s to 10 m/s

momentum = mv = 2(10) = 20 kg•m/s

KE = ½mv² = ½(2)10² = 100 J

Unfortunately, your answer selection does not have this answer as an option.

4 0

3 years ago

Which process in the water cycle MUST occur directly before water can become groundwater?

Darina [25.2K]

The answer is A.<span>infiltration</span>

5 0

3 years ago

Sabiendo que el indice de refracción dela gua es 1,33 calcula el ángulo de refracción resultante para un rayo de luz que incide

Kaylis [27]

Answer:

35.16 degrees

Explanation:

Knowing that the index of refraction of the guide is 1.33, calculate the resulting angle of refraction for a ray of light that falls on a pool with an angle of incidence of 50º

Refractive index, n = 1.33

The angle of incidence, i = 50°

We need to find the angle of refraction. let it is r. It can be calculated using Snells law as follows:

$n=\dfrac{\sin i}{\sin r}\\\\\sin r=\dfrac{\sin i}{n}\\\\r=\sin^{-1}(\dfrac{\sin i}{n})\\\\r=\sin^{-1}(\dfrac{\sin 50}{1.33})\\\\r=35.16^{\circ}$