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Sedaia [141]
3 years ago
12

When tuning a guitar, a musician plays two strings at once. These sound waves overlap and often appear to get louder and softer

if the strings are not in tune. This interaction of overlapping waves is called
Physics
1 answer:
Ymorist [56]3 years ago
3 0
It's called ' interference '. 

If the strings are 'in tune' (same frequency) and in phase, then
they overlap to make a louder sound ... CONstructive interference.

If the strings are 'in tune' (same frequency) but out of phase, then
they overlap to make a softer sound ... DEstructive interference.

If the strings are 'out of tune' (different frequencies), then they overlap
to make a sound that's louder at some times and softer at other times.
The louder and softer pattern creates a new sound, called the 'beat'.
Its frequency is the difference in the frequencies of the two strings.
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Two airplanes leave an airport at the same time. The velocity of the first airplane is 750 m/h at a heading of 51.3°. The veloci
abruzzese [7]
Refer to the diagram shown below.

In 2.4 hours, the distance traveled by the first airplane heading a 51.3° at 750 mph is 
a = 750*2.4 = 1800 miles.

The second airplane travels
b = 620*2.4 = 1488 mile

The angle between the two airplanes is
163° - 51.3° = 111.7°

Let c =  the distance between the two airplanes after 2.4 hours.
From the Law of Cosines, obtain
c² = a² + b² - 2ab cos(111.7°)
    = 3.24 x 10⁶ + 2.2141 x 10⁶
c = 2335.41 miles

Answer: 2335.4 miles

4 0
3 years ago
Read 2 more answers
You use 8x binoculars were used on a warbler (14cm long) in a tree 18cm away. What angle (in degrees) does the image of the warb
mafiozo [28]

Answer:

The angle it subtend on the retina is  \theta_z = 0.44586^o    

Explanation:

From the question we are told that

     The length of the warbler is  L = 14cm = \frac{14}{100} = 0.14m

      The distance from the binoculars is    d = 18cm = \frac{18}{100} = 0.18m

        The magnification of the binoculars is  M =8

Without the 8 X binoculars the  angle made with the angular size of the object  is mathematically represented as

          \theta = \frac{L}{d}

        \theta  = \frac{0.14}{0.18}

           = 0.007778 rad

Now magnification can be represented mathematically as

         M = \frac{\theta _z}{\theta}

Where \theta_z is the angle the image of the warbler subtend on your retina when the   binoculars i.e the  binoculars zoom.

So

      \theta_z = M * \theta

=>    \theta_z =8 * 0.007778

            = 0.0622222224

Generally the conversion to degrees can be mathematically evaluated as

             \theta_z = 0.062222224 * (\frac{360 }{2 \pi rad} )

              \theta_z = 0.44586^o  

7 0
3 years ago
How do scientists use inference?
alexgriva [62]
Their inferences are based on evidence that they collect during their investigations. Readers learn that scientists gather and interpret evidence and draw conclusions based on this evidence. ... Once scientists have gathered evidence, they use it to make inferences about the things they are investigating.
5 0
3 years ago
Can someone help on this I'm really stuck
castortr0y [4]
Here, "Wavelength is same for both waves" it is the distance between two crests or two consecutive troughs, so, it is constant for both of them, you can easily figure it out.

In short, Your Answer would be "Wavelength"

Hope this helps!
5 0
3 years ago
Cart 1 of mass m is traveling with speed 2vo in the +x-direction when it has an elastic collision with cart 2 of
iogann1982 [59]

Answer:

Explanation:

Momentum conservation

m2v_0+2mv_0=mv_1+2mv_2 \quad (1/m) \quad 4v_0=v_1+2v_2\\

Kinetic energy conservation

\displaystyle \frac{1}{2}m(2v_0)^2+\frac{1}{2}2mv_0^2=\frac{1}{2}mv_1^2+\frac{1}{2}2mv_2^2 \quad (1/m) \quad 6v_0^2=v_1^2+2v_2^2

Solve the system

6 0
3 years ago
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