Answer:25,06 kJ of energy must be added to a 75 g block of ice.
ΔHfusion(H₂O) = 6,01 kJ/mol.
T(H₂O) = 0°C.
m(H₂O) = 75 g.
n(H₂O) = m(H₂O) ÷ M(H₂O).
n(H₂O) = 75 g ÷ 18 g/mol.
n(H₂O) = 4,17 mol.
Q = ΔHfusion(H₂O) · n(H₂O)
Q = 6,01 kJ/mol · 4,17 mol
Q = 25,06 kJ.
Explanation:
This reaction is most likely to fall under SN2 because the
thing called carbonication does not occur in SN1. The carbon forms a partial
bond with the nucleophile during the intermediate phase and the leaving group.
So for this question the reaction will fall under SN2.
Answer:
1 cm/s
Explanation:
From the question given above,
the student is trying to convert 0.010 m/s to a number in cm/s.
Thus, we can convert 0.010 m/s to cm/s as illustrated below:
Recall:
1 m/s = 100 cm/s
Therefore,
0.010 m/s = 0.010 m/s × 100 cm/s ÷ 1 m/s
0.010 m/s = 1 cm/s
Therefore, 0.010 m/s is equivalent to 1 cm/s
Answer:
glucose and oxygen
Explanation:
Glucose and oxygen are needed for cellular respiration to occur:)
Answer:
ml and cm3
Explanation:
millilitres and centimetres cubed or litres and metres cubed. Any unit of measuring liquid if the substance is a a liquid or a unit cubed
