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solniwko [45]
3 years ago
7

A thermometer is placed in a beaker full of water that has been sitting on the lab table for a few hours. The beaker is placed o

n a ring stand and heated over a Bunsen burner for 4 minutes. After 4 minutes, the temperature is taken again. Find the temperature change of the water if the temperature of the room is 26°C.
A)26°CB)73°CC)99°CD)124°C
Chemistry
2 answers:
krek1111 [17]3 years ago
7 0
Based on the information I would assume B, 73 degrees...

It shouldn't be A, 4 minutes on the burner should increase the temperature.

If it were D, it would be beyond boiling, and water takes a decent amount of energy to heat, D should be all vapor.

Same logic for C, it's basically almost boiling.

I would say 73 degrees seems most reasonable for 4 minutes.
Nat2105 [25]3 years ago
3 0

Answer:

B 73 degress celcius

Explanation:

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the heat of fusion of acetone is 5.7 kJ/mol. Calculate to two significant figures the entropy change when 6.3 mol of acetone mel
shtirl [24]

<u>Answer:</u> The entropy change of the process is 2.0\times 10^2J/K

<u>Explanation:</u>

To calculate the entropy change for different phase at same temperature, we use the equation:

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where,  

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\Delta H_{f} = enthalpy of fusion = 5.7 kJ/mol = 5700 J/mol    (Conversion factor:  1 kJ = 1000 J)

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Putting values in above equation, we get:

\Delta S=\frac{6.3mol\times 5700J/mol}{178.3K}\\\\\Delta S=201.4J/K=2.0\times 10^2J/K

Hence, the entropy change of the process is 2.0\times 10^2J/K

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