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PolarNik [594]
3 years ago
13

What is the correctly balanced chemical equation for the reaction of KOH and H2SO4

Chemistry
1 answer:
True [87]3 years ago
4 0

KOH + H2SO4 —> K(+) + HSO4(-) + H2O

Or a total reaction

2 KOH + H2SO4 —> 2 K(+) + SO4(2-) + 2 H2O

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A chemist must prepare 300.0mL of nitric acid solution with a pH of 0.70 at 25°C. He will do this in three steps: Fill a 300.0mL
d1i1m1o1n [39]

<u>Answer:</u> The volume of concentrated solution required is 9.95 mL

<u>Explanation:</u>

To calculate the pH of the solution, we use the equation:

pH=-\log[H^+]

We are given:

pH = 0.70

Putting values in above equation, we get:

0.70=-\log[H^+]

[H^+]=10^{-0.70}=0.199M

1 mole of nitric acid produces 1 mole of hydrogen ions and 1 mole of nitrate ions.

Molarity of nitric acid = 0.199 M

To calculate the volume of the concentrated solution, we use the equation:

M_1V_1=M_2V_2

where,

M_1\text{ and }V_1 are the molarity and volume of the concentrated nitric acid solution

M_2\text{ and }V_2 are the molarity and volume of diluted nitric acid solution

We are given:

M_1=7.0M\\V_1=?mL\\M_2=0.199M\\V_2=350mL

Putting values in above equation, we get:

7.0\times V_1=0.199\times 350.0\\\\V_1=\frac{0.199\times 350}{7.0}=9.95mL

Hence, the volume of concentrated solution required is 9.95 mL

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2 years ago
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How does the picture show that the inner core spins faster than the outer core?
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Which of the following mixtures may be act as a buffer solution?
lions [1.4K]

Answer:

B) HF, NaF

Explanation:

  • A buffer solution is made up of a weak acid and its conjugate base.
  • In this case, HF is a weak acid and NaF is the conjugate base, therefore the mixture of HF,  and NaF would make a perfect buffer solution.
  • The buffer would have the weak acid HF and its conjugate base, F- which comes from the soluble salt NaF.
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3 years ago
In NMR if a chemical shift(δ) is 211.5 ppm from the tetramethylsilane (TMS) standard and the spectrometer frequency is 556 MHz,
Vika [28.1K]

Answer:

The answer is: 11759 Hz

Explanation:

Given: Chemical shift: δ = 211.5 ppm, Spectrometer frequency = 556 MHz = 556 × 10⁶ Hz

In NMR spectroscopy, the chemical shift (δ), expressed in ppm, of a given nucleus is given by the equation:

\delta (ppm) = \frac{Observed\,frequency (Hz)}{Frequency\,\, of\,\,the\,Spectrometer (MHz)} \times 10^{6}

\therefore Observed\,frequency (Hz)= \frac{\delta (ppm)\times Frequency\,\, of\,\,the\,Spectrometer (MHz)}{10^{6}}

Observed\,frequency= \frac{211.5 ppm \times 556 \times 10^{6} Hz}{10^{6}} = 11759 Hz

<u>Therefore, the signal is at 11759 Hz from the TMS.</u>

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The unit for work is ENERGY
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