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Natali5045456 [20]
2 years ago
15

X/12 = -11 ugh so hard help me pls to make my sad face happy :(

Mathematics
2 answers:
Otrada [13]2 years ago
7 0

Answer:

-132

Step-by-step explanation:

x/12 = -11

<u>⋅ 12 = ⋅ 12</u>

x = -132

svet-max [94.6K]2 years ago
6 0
X/12 = -11

Isolate the variable using inverse operations.
(multiple both sides by 12)

x= -11(12)

Simplify.

*x= -132*

Hope this helps :))
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Answer: 2 7/10

Step-by-step explanation:

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2 years ago
Please please help me I don’t even know how to do this
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7 0
3 years ago
Read 2 more answers
Translate the figure 2 units left and 7 units down.
STALIN [3.7K]

The translation of the given figure will have vertices, <u>A'(1,2),</u> <u>B'(3,2),</u> <u>C'(3,-5),</u> and <u>D(-1,-3)</u> from the initial vertices A(3,9), B(5,9), C(5,2), and D(1,4). The figure is attached.

In the question, we are asked to translate the given figure 2 units left and 7 units down.

In the translation, the left-right movement implies the change in the x-coordinate, whereas the up-down movement implies the change in the y-coordinate.

For any point P(x, y) the given rule says that after translation,

P(x, y) becomes P'(x - 2, y - 7).

The coordinates of the given figure are:

A(3,9), B(5,9), C(5,2), and D(1,4).

After translation, these points can be shown as:

A(3,9) becomes A'(1,2).

B(5,9) becomes B'(3,2).

C(5,2) becomes C'(3,-5).

D(1,4) becomes D'(-1,-3).

Thus, the translation of the given figure will have vertices, <u>A'(1,2),</u> <u>B'(3,2),</u> <u>C'(3,-5),</u> and <u>D(-1,-3)</u> from the initial vertices A(3,9), B(5,9), C(5,2), and D(1,4). The figure is attached.

Learn more about translations at

brainly.com/question/1400185

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7 0
2 years ago
At a high school the student government is made up of 5 seniors, 4 juniors, 3 sophomores and 2 freshmen. If there are 8 seniors,
hjlf

Answer:

  • 32598720

Step-by-step explanation:

<u>Combination for the school government requires:</u>

  • 5 out of 8 seniors = 8! / 3!5! = 6*7*8/2*3 = 7*8 = 56
  • 4 out of 9 juniors = 9! / 4!5! = 6*7*8*9/2*3*4= 7*2*9 = 126
  • 3 out of 12 sophomores = 12! / 3!9! = 10*11*12/2*3 = 10*11*2 = 220
  • 2 out of 7 fishermen = 7! / 2!5! = 6*7/2 = 21

<u>So number of total ways is:</u>

  • 56*126*220*21 = 32598720
5 0
2 years ago
For his troops' popcorn fundraiser sale, Mike sold caramel corn for $10, buttered microwave popcorn for $8, and lightly buttered
Bad White [126]
\bf \begin{cases}&#10;c=\textit{caramel corn}\\&#10;b=\textit{buttered microwave popcorn}\\&#10;p=\textit{lightly buttered popcorn}&#10;\end{cases}

so... he sold 400 items, that means, whatever those quantities of c,b,p are, they add up to 400, thus

c+b+p = 400

now, the "c" sold for $10
the "b" sold for $8
and the "p" sold for $7

so, the amount of revenue on the "c" is 10 * c, or 10c
the revenue on "b" is 8*b or 8b
and the revenue on "p" is 7*p or 7p

whatever those amounts are, they ended up in $3,272
thus
10c + 8b + 7p = 3,272

now, he sold more lightly buttered, or "p", than just buttered corn or "b"
he actually sold twice as much, so whatever "b" is, "p" is twice that much
or 
p = 2b

thus      \bf \begin{cases}&#10;c+b+\boxed{p}=400\\\\&#10;\boxed{p}=2b\qquad thus\\\\&#10;c+b+\boxed{2b}=400\qquad or\\\\&#10;c+3b=400\implies c=\underline{400-3b}\\&#10;--------------\\&#10;10c+8b+7p=3272\qquad or\\\\&#10;10(\underline{400-3b})+8b+7(\boxed{2b})=3272&#10;\end{cases}

solve for "b", to see how many buttered microwave popcorn Mike sold

how many lightly buttered?  well, p = 2b
how many caramel ones?   well  c = 400 - 3b
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