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Fed [463]
3 years ago
14

Consider the circuit. Switches are added at points A, B, C, and D. All the switches are closed EXCEPT the switch at position D,

which is left open. What is the result of this?
Physics
2 answers:
lora16 [44]3 years ago
7 0

Answer:

A I just had it on usa test prep

Explanation:

Liono4ka [1.6K]3 years ago
5 0

answer: a) only light 4 will go out.

i did the usatestprep.

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Which material is a composite? A. gold B.silicon C.polycarbonate D.aluminum
sweet [91]

Answer:

I think gold

Explanation:

6 0
3 years ago
Will is a scientist. He’s designing a spacecraft that would allow people to land on Mars. Will’s mass on Earth is 75 kilograms.
Vesnalui [34]
Mass will remain unchanged, always.  His weight, which is the gravitational force acting on that mass will be less in this case.
6 0
3 years ago
Read 2 more answers
Vector of magnitude 15 is added to a vector of magnitude 25. The magnitude of this sum
loris [4]

Explanation:

Given that,

Magnitude of vector A, |A| = 15

Magnitude of vector B, |B| = 25

We need to find the magnitude of this sum.

The maximum sum of the resultant vector,

R_{max}=|A_1|+|A_2|\\\\=15+25\\\\=45

The minimum sum of the resultant vector,

R_{min}=|A_1|-|A_2|\\\\=15-25\\\\=-10

So, the magnitude of this sum either 45 or -10.

6 0
3 years ago
Calcula el valor de la velocidad de las ondas sonoras en el agua sabiendo que su
dybincka [34]
  1. La velocidad de las ondas sonoras es aproximadamente 1469,694 metros por segundo.
  2. La longitud de onda de las ondas sonoras es 1,470 metros.

1) Inicialmente, debemos determinar la velocidad de las ondas sonoras a través del agua (v), en metros por segundo:

v = \sqrt{\frac{K}{\rho} } (1)

Donde:

  • K - Módulo de compresibilidad, en newtons por metro cuadrado.
  • \rho - Densidad del agua, en kilogramos por metro cúbico.

Si sabemos que \rho = 1\times 10^{3}\,\frac{kg}{m^{3}} y K = 2,16\times 10^{9}\,\frac{N}{m^{2}}, entonces la velocidad de las ondas sonoras es:

v = \sqrt{\frac{2,16\times 10^{9}\,\frac{N}{m^{2}}}{1\times 10^{3}\,\frac{kg}{m^{3}} } }

v\approx 1469,694\,\frac{m}{s}

La velocidad de las ondas sonoras es aproximadamente 1469,694 metros por segundo.

2) Luego, determinamos la longitud de onda (\lambda), en metros, mediante la siguiente fórmula:

\lambda = \frac{v}{f} (2)

Donde f es la frecuencia de las ondas sonoras, en hertz.

Si sabemos que v\approx 1469,694\,\frac{m}{s} y f = 1000\,hz, entonces la longitud de onda de las ondas sonoras es:

\lambda = \frac{1469,694\,\frac{m}{s} }{1000\,hz}

\lambda = 1,470\,m

La longitud de onda de las ondas sonoras es 1,470 metros.

Para aprender más sobre las ondas sonoras, invitamos a ver esta pregunta verificada: brainly.com/question/1070238

6 0
2 years ago
Name two index fossils. Why are these fossils important to the practice of relative aging?
Inessa05 [86]
Dinosaur and bird so u can see how they developed and how they aged to become something popular<span />
8 0
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