1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Strike441 [17]
3 years ago
7

You throw a 3.00 N rock vertically into the air from ground level. You observe that when it is 15.0 m above the ground, it is tr

aveling at 25.0 m/s upward. Use the work–energy theorem to find (a) the rock’s speed just as it left the ground and (b) its maximum height.
Physics
1 answer:
True [87]3 years ago
5 0

Answer:

a) 30.32 m/s

b) 46.855 m

Explanation:

F =  Force

g = Acceleration due to gravity = 9.81 m/s²

s = Displacement

u = Initial velocity

v = Final velocity

Work done

W=Fs\\\Rightarrow W=mgs\\\Rightarrow W=mg15

From Work Energy theorem

W=\frac{1}{2}m(v^2-u^2)\\\Rightarrow 2W-mv^2=-mu^2\\\Rightarrow mu^2=mv^2-2W\\\Rightarrow mu^2=mv^2-2(mgs)\\\Rightarrow u^2=v^2-2gs\\\Rightarrow u=\sqrt{v^2-2gs}\\\Rightarrow u=\sqrt{25^2-2\times -9.81\times 15}\\\Rightarrow u=30.32\ m/s

Initial velocity of the rock is 30.32 m/s

mgs=\frac{1}{2}m(v^2-u^2)\\\Rightarrow gs=\frac{1}{2}(-u^2)\\\Rightarrow s=\frac{\frac{1}{2}(-u^2)}{g}\\\Rightarrow s=\frac{\frac{1}{2}(-30.32^2)}{-9.81}\\\Rightarrow s=46.855\ m

Maximum height that the rock reached is 46.855 m

You might be interested in
The theoretical line perpindicular to the surface where a light ray hits a mirror is called the
valkas [14]
That's called the "normal" to the surface at that point.
3 0
3 years ago
How would the self-inductance, l, of a coil change if you would increase its radius by a factor of two and increase its length b
pochemuha

The self-inductance of a coil will change by 8 times its original value by increasing its radius value by 2 and increasing the length of the coil by 2.

Self-Inductance: -

The definition of self-inductance is the induction of a voltage in a wire that carries current when the current in the wire is changing. In the instance of self-inductance, the circuit itself induces a voltage through the magnetic field produced by a changing current.

We know that the self-inductance of the coil is denoted by: -

L= µ *π*(r)^2*(N)^2*l

Where

L= Self-Inductance of the coil

µ= Magnetic Permeability Constant

r= Radius of the coil

l= Length of the coil

N= Number of turns of the coil

Here Self-inductance of the coil is directly proportional to the length of the coil and the square of the radius of the coil.

So,

On increasing the radius of the coil by a factor of 2 and the length of the coil by 2 the self-inductance of the coil increases by 8 times its original value.

Learn more about Self-Inductance here: -

" brainly.com/question/15293029 "

#SPJ4

3 0
2 years ago
Part C Let’s start the analysis by looking at your “extreme usage” cases. Compare the two cases in detail—low usage period versu
Serga [27]

Answer:

Day 7 DataUsage notes (since last reading)day & datetimekWh readingkWh usedhours elapsedavg. kW usedb.Usage Extremes: Data CollectionFor this experiment, you’ll measure electrical usage during a time period when you expect to havevery light electrical usage (for instance, while you’re asleep at night or during the day when no oneis at home). Likewise you’ll measure electrical usage during a time period when you expect to have heavier than average electrical usage. This time period might be in the evening, when lights and other appliances are on. Both of these time periods should be at least 4 hours long, to increase the accuracy of your results. Record your results in the tables below for each situation. For each time period, you’ll need to takean initial and a final reading.Type your response here:Low Usage - Initial Readingday & datetimekWh readingLow Usage - Final ReadingEnergy Usage Notesday & datetimekWh readingkWh usedhours elapsedavg. kW usedHigh Usage - Initial Readingday & datetimekWh reading4

6 0
3 years ago
A rocket has a mass 280(103) slugs on earth. Specify its mass in SI units, and its weight in SI units.
saw5 [17]

To solve this problem we will apply the concepts related to the conversion of units for which we will have that 1 slug is equal to 14.59kg. At the same time we will use Newton's second law for which weight is defined as the product between mass and acceleration (Due to gravity). This is then

A: Using the conversion ratio of slug to kilogram we have to,

1 slug = 14.59kg

Then

m = 280*10^3 slugs (\frac{14.59kg}{1slug})

m = 4.09*10^6kg

B: Using Newton's second law we have to,

W = mg

W = (4.09*10^6)(9.8)

W = 40034960N\approx 4*10^7N

8 0
3 years ago
How to calculate ?Help!!!
Alona [7]
How to calculate what?
6 0
4 years ago
Other questions:
  • What are the products of a neutralization reaction
    13·2 answers
  • Which statement describes the difference between renewable and nonrenewable energy sources
    14·1 answer
  • A 3.04 kg particle is located on the x-axis at xm = −8 m, and a 5.61 kg particle is on the x-axis at xM = 3.56 m. Find the coord
    11·1 answer
  • A box is sitting on the ground and weighs 100 kg and the coefficient of friction is 0.23. Is it easier to push by applying the f
    7·1 answer
  • A student standing on a cliff that is a vertical height d = 8.0 m above the level ground throws a stone with velocity v0 = 22 m/
    7·1 answer
  • As temperature increases what energy decreases
    10·1 answer
  • Refer to the first diagram. What is the weight of the person hanging on the end of the seesaw in Newtons?
    11·1 answer
  • Substance A has a higher heat capacity than substance B. If the same amount of heat is added to both substances, which substance
    10·2 answers
  • What are the energy transfers in a torch?
    7·1 answer
  • A car's velocity changes from 40 m/s to 30 m/s in 40 seconds. What is the
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!