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SIZIF [17.4K]
3 years ago
14

Which of the following is part of the central nervous system?

Chemistry
2 answers:
OLga [1]3 years ago
3 0

The brain is part of the central nervous system.

Nerves and sensors are part of the peripheral nervous system. Only the brain and spinal cord make the central nervous system.

MrRa [10]3 years ago
3 0

the first person to answer was correct. it was A. i got the question correct on my quiz

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Into how many peaks will each proton shown in red be split
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The proton has two adjacent protons, so it splits into three peaks, a triplet. The proton has three adjacent protons, so it splits into four peaks, a quartet.
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Given the following chemical reaction: 2 O2 + CH4 CO2 + 2 H2O What mass of oxygen is required to completely react with 20 grams
Jobisdone [24]
The chemical equation is:
CH₄ + 2O₂ → CO₂ + 2H₂O

First, we calculate the moles of methane present using:
Moles = mass / molecular mass
Moles = 20 / 16
Moles = 1.25

Next, we may observe from the chemical equation that the molar ratio between methane and oxygen is 1 : 2
So the moles of oxygen required are 2 x 1.25
2.5 moles of oxygen required

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4 0
3 years ago
A bowling ball, a baseball, a tennis ball, and a ping-pong ball are all dropped from a height of 2 meters. Which has the most ki
mr_godi [17]

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6 0
3 years ago
When an excited electron in an atom moves to the ground state, the electron
kodGreya [7K]

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7 0
3 years ago
Read 2 more answers
2. A quantity of 1.922g of methanol (CH3OH) was burned in a constant-volume
Cerrena [4.2K]
Mass of methanol (CH3OH) = 1.922 g
Change in Temperature (t) = 4.20°C
Heat capacity of the bomb plus water = 10.4 KJ/oC
The heat absorbed by the bomb and water is equal to the product of the heat capacity and the temperature change.
Let’s assume that no heat is lost to the surroundings. First, let’s calculate the heat changes in the calorimeter. This is calculated using the formula shown below:
qcal = Ccalt
Where, qcal = heat of reaction
Ccal = heat capacity of calorimeter
t = change in temperature of the sample
Now, let’s calculate qcal:
qcal = (10.4 kJ/°C)(4.20°C)
= 43.68 kJ
Always qsys = qcal + qrxn = 0,
qrxn = -43.68 kJ
The heat change of the reaction is - 43.68 kJ which is the heat released by the combustion of 1.922 g of CH3OH. Therefore, the conversion factor is:
5 0
3 years ago
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