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xeze [42]
3 years ago
15

Write the equation in slope-

Mathematics
1 answer:
sashaice [31]3 years ago
4 0

Answer:

y= 13/7x+90/7

Step-by-step explanation:

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Find a.b.c if one of the angles is 150
Zepler [3.9K]
Triangle has 180 degrees
1 side=180
Then 180-150= 30 degrees
30/2 (for the other two sides)= 15
So, 150 degrees, 15 degrees and 15 degrees.
So it’s probably an isosceles triangle as the two bottom angles are the same number of degrees

Hope this helps :)
3 0
3 years ago
{18 • [(25 + 15) ÷ 4] + 25} • 12 + 16 • 3
Leviafan [203]
2,508 says my calulator
3 0
3 years ago
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A spherical balloon is inflated with gas at a rate of 500 cubic centimeters per minute. Find the rates of change of the radius w
-BARSIC- [3]

Answer:

for r= 70 cm

the rate is 0.008cm/s

for r=95cm

the rate= 0.0044cm/s

Step-by-step explanation:

kindly find attached a rough sketch of the circle and a detailed solution of the problem.

Given data

rate dv/dt=500cm^3

r=70cm

r=95cm

4 0
2 years ago
Anyone know this because I need help !!!!
Mila [183]

Answer:

90 clockwise

Step-by-step explanation:

rotate it by 90 degrees. it lines up

5 0
3 years ago
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Simplify: cos2x-cos4 all over sin2x + sin 4x
GrogVix [38]

Answer:

\frac{\cos\left(2x\right)-\cos\left(4x\right)}{\sin\left(2x\right)+\sin\left(4x\right)}=\tan\left(x\right)

Step-by-step explanation:

\frac{\cos\left(2x\right)-\cos\left(4x\right)}{\sin\left(2x\right)+\sin\left(4x\right)}

Apply formula:

\cos\left(A\right)-\cos\left(B\right)=-2\cdot\sin\left(\frac{A+B}{2}\right)\cdot\sin\left(\frac{A-B}{2}\right) and

\sin\left(A\right)+\sin\left(B\right)=2\cdot\sin\left(\frac{A+B}{2}\right)\cdot\sin\left(\frac{A-B}{2}\right)

We get:

=\frac{-2\cdot\sin\left(\frac{2x+4x}{2}\right)\cdot\sin\left(\frac{2x-4x}{2}\right)}{2\cdot\sin\left(\frac{2x+4x}{2}\right)\cdot\cos\left(\frac{2x-4x}{2}\right)}

=\frac{-\sin\left(\frac{2x-4x}{2}\right)}{\cos\left(\frac{2x-4x}{2}\right)}

=\frac{-\sin\left(\frac{-2x}{2}\right)}{\cos\left(\frac{-2x}{2}\right)}

=\frac{-\sin\left(-x\right)}{\cos\left(-x\right)}

=\frac{-\cdot-\sin\left(x\right)}{\cos\left(x\right)}

=\frac{\sin\left(x\right)}{\cos\left(x\right)}

=\tan\left(x\right)

Hence final answer is

\frac{\cos\left(2x\right)-\cos\left(4x\right)}{\sin\left(2x\right)+\sin\left(4x\right)}=\tan\left(x\right)

6 0
2 years ago
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