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3 years ago

HELP!!!!! I AM DESPERATE!!!!!

Mathematics

2 answers:

vfiekz [6]3 years ago

4 0

Answer:

1. Linear

2. Linear

3. Non-Linear

4. Non-Linear

5. Linear

6. Non-Linear

7. Linear

8. Non-Linear

9. Linear

The code should be LLNNLNLNL

ELEN [110]3 years ago

3 0

L L N N L N L N L

This should be your code

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3200 dollars is placed in an account with an annual interest rate of 6.5%. To the nearest year, how long will it take for the ac

madam [21]

4 yrs

Step-by-step explanation:

Formulae for simple interest is;

A= P (1 + rt) Whereby;

A = Total Accrued Amount (principal + interest)

P = Principal Amount

I = Interest Amount

r = Rate of Interest per year in decimal; r = R/100

R = Rate of Interest per year as a percent; R = r * 100

t = Time Period involved in months or years

15300 = 3200 (1 + 106.5/100 *t)

15300/3200 = 1 + 1.065t

4.78125 – 1 = 1.065t

3.78125 = 1.065t

3.78125/1.065 = t

3.55 = t

Rounded off to the nearest whole number;

= 4

5 0

3 years ago

If u mix 2.5 cups of water with 1/3 cup of lemonade what would the answer be

schepotkina [342]

The total volume I suppose is what you are asking.
You can simplify this into 1/3 = .33
2.5 + .33 = 2.88 cups.

6 0

4 years ago

I need help, i don’t understand how to do it

3241004551 [841]

Hai , you can use Pythagoras Theorem to find the length which is hypotenuse.

It will be 7^2 + 3^2 = 58

square root 58 and you will get 7.62

Hope this helps and i am sorry if my answer was wrong .

3 0

3 years ago

The vertex of f(x) = 3x ^2+ 5x + 2 is a:<br> minimum<br> maximum<br> none of these

timama [110]

Answer:

minimum

Step-by-step explanation:

Given a quadratic in standard form f(x) = ax² + bx + c ( a ≠ 0 )

• If a > 0 then vertex is a minimum

• If a < 0 then vertex is a maximum

f(x) = 3x² + 5x + 2 ← is in standard form

with a = 3

Since a > 0 then vertex is a minimum

6 0

3 years ago

A physical education teacher plans to divide the seventh graders at Wilson Middle School into teams of equal size of year-ending

Crank

Step-by-step explanation:

Consider the provided information.

The total number of students are: 24+26+21=71

He wants each team will have the same number of students between 5 and 9.

The number between 5 to 9 are 6, 7 and 8.

The number 71 is a prime number so we need to divide the 71 students in group so that minimum students left without team.

Dividing 6 students in each group.

Number of teams: $\frac{71}{6}$ = 11 teams and 5 students.

Dividing 7 students in each group.

Number of teams: $\frac{71}{7}$ = 10 teams and 1 students.

Dividing 8 students in each group.

Number of teams: $\frac{71}{8}$ = 8 teams and 7 students.

Thus, we can not divide 71 students into equal teams, but 70 divided by 7 gives the least students left out i.e 10 teams each with 7 students and only 1 student will remain at last.

6 0

3 years ago