The engine displacement in cubic nanometer (nm³) is 8.785×10²⁴ nm³
<h3>Data obtained from the question </h3>
- Displacement in in³ = 536 in³
- Displacement in nm³ =?
<h3>Conversion scale </h3>
1 in³ = 1.639×10²² nm³
With the above convesion scale we can obtain the displacement in nm³
<h3>How to determine the displacement in nm³</h3>
1 in³ = 1.639×10²² nm³
Therefore,
536 in³ = 536 × 1.639×10²²
536 in³ = 8.785×10²⁴ nm³
Thus, the displacement in nm³ is 8.785×10²⁴ nm³
Learn more about conversion:
brainly.com/question/2139943
Answer:
C = 0.7385J/g°C
Explanation:
Heat energy (Q) = 54J
Mass (m) = 2.47g
Initial temperature (T1) = 17.10°C
Final temperature (T2) = 46.70°C
Specific heat capacity of substance (c) = ?
Heat energy of a substance (Q) = Mc∇T
Q = heat energy
M = mass of the substance
C = specific heat capacity of the substance
∇T = change in temperature of substance = T2 - T1
Q = mc∇T
Q = mc (T2 - T1)
54 = 2.47 * c * (46.70 - 17.10)
54 = 2.47 * 29.6 * c
54 = 73.112c
C = 54 / 73.112
C = 0.7385
Specific heat capacity of the substance is 0.7385J/g°C
B.
The specific heat capacity of the above substance does not match any metal in the periodic table, however the closest to it was potassium with a value of 0.7536J/g°C and silicone with value of 0.711756J/g°C
Answer:2097.5998675091255
Explanation:
PROTON: Positive (+) charge. Relative mass of 1. Found in the nucleus.
NEUTRON: Neutral charge. Relative mass of 1. Found in the nucleus.
ELECTRON: Negative (-) charge. Relative mass of .0005. Found on the outside of the nucleus.
Chadwick proved the existence of neutrons - elementary particles devoid of any electrical charge.
Rutherford discovered alpha and beta rays and proposed the mass of radioactive decay. Postulated the nuclear structure of the atom.
J.J Thompson proposed the plum pudding model of the atom. Showed that all atoms contain tiny negatively charged subatomic particles or electrons.