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3 years ago

PLEASE HELP Given: △ABC, m∠B=90° AB=12, BC=16, BK ⊥ AC . Find: AC and BK.

Mathematics

2 answers:

77julia77 [94]3 years ago

7 0

Answer:

AC = 20

BK = 9.6

Step-by-step explanation:

AC is found using the Pythagorean theorem in the usual way:

AC² = AB² + BC²

AC² = 12² + 16² = 144 +256 = 400

AC = √400

AC = 20

You may recognize this is a 3-4-5 triangle scaled by a factor of 4.

Then BK is found using similar triangles. All of the triangles in the figure are similar*, so ...

long side / hypotenuse = BC/AC = BK/AB

BK = AB(BC/AC) = 12(16/20) = 12×0.8

BK = 9.6

Read more on Brainly.com - brainly.com/question/13203483#readmore

liraira [26]3 years ago

3 0

Since m∠B = 90°, then ΔABC is a right triangle, so Pythagorean Theorem can be used to solve for AC.

AB² + BC² = AC²

12² + 16² = AC²

144 + 256 = AC²

400 = AC²

20 = AC

The placement of point K is not given. Is it on AC, inside the triangle, or outside the triangle? In order to find the length, you need to know where it is placed.

Answer: AC = 20, BK = 35/3 ≈ 11.67

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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Answer:

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