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Makovka662 [10]
3 years ago
15

Solve the equation 3y + xy = 23 for the variable y.

Mathematics
1 answer:
mixas84 [53]3 years ago
4 0

y = 23/(3 + x)

Step-by-step explanation:

\begin{aligned}\rm 3y + xy&= 23\\\rm y(3 + x)&= 23\\\bf y&=\bf\frac{23}{3+x}\end{aligned}

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Show how to solve the problem 378 x 6 using place value with regrouping. Explain how you knew when to regroup.
KIM [24]

<u>Answer</u>

2,268


<u>Explanation</u>

<u> </u>

<u>By grouping 378 ca</u>n be written as,

378 = 300 + 70 + 8

6× 378 = 6 × (300 + 70 + 8)

             = (6×300) + (6×70) + (6×8)

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8 0
3 years ago
The figure shows a circle within a square. Find the circumference of the circle let π = 3.14. <br> ​
Andru [333]

The side of the square = 16 in

When a circle is inscribed in a square, the length of each side of the square is equal to the diameter of the circle.

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8 0
2 years ago
Write the fraction in the simplest form 6/8
vladimir1956 [14]
\frac{6}{8} = \frac{3\times 2}{4\times 2} =\boxed{\bf{ \frac{3}{4} }}
7 0
3 years ago
Read 2 more answers
Question:
alexandr1967 [171]

Answer:

Part 1) The draw in the attached figure

Part 2) m\angle ABD=50^o

Step-by-step explanation:

Part 1)  Draw the described circle

The draw in the attached figure

Part 2) What is the measure of angle ABD

step 1

Find the measure of arc AD

Remember that

arc\ AD+arc\ DC+arc\ AC=360^o ----> by complete circle

substitute the given values

arc\ AD+124^o+68^o=360^o

arc\ AD=360^o-192^o=168^o

step 2

Find the measure of angle ABD

we know that

The measurement of the external angle is the half-difference of the arches that comprise

In this problem

The measure of angle ABD is an external angle

so

m\angle ABD=\frac{1}{2} [arc\ AD-arc\ AC]

substitute the given values

m\angle ABD=\frac{1}{2} [168^o-68^o]=50^o

5 0
3 years ago
Solve for z.<br> -cz+6z= tz+83
Likurg_2 [28]
Hello i saw you question and I knew the answer was this, it is a fraction

z= v-83
     -----
      c+t-6
3 0
3 years ago
Read 2 more answers
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