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Alisiya [41]
3 years ago
15

g When copper(II) chloride and sodium carbonate solutions are combined, solid copper(II) carbonate precipitates, leaving a solut

ion of sodium chloride. Write the conventional equation, total ionic equation, and net ionic equation for this reaction. (Use the lowest possible coefficients. Be sure to specify states such as (aq) or (s). If a box is not needed, leave it blank.)
Chemistry
1 answer:
Elden [556K]3 years ago
5 0

Answer:

When copper(II) chloride and sodium carbonate solutions are combined, solid copper(II) carbonate precipitates, leaving a solution of sodium chloride. Write the conventional equation, total ionic equation, and net ionic equation for this reaction.

Explanation:

The word equation for the reaction is:

Copper (II) chloride(aq) + sodium carbonate (aq) ->sodium chloride (aq) +           copper carbonate(s)

The balanced chemical equation of the reaction is:

CuCl_2(aq)+Na_2CO_3(aq)->2NaCl(aq)+CuCO_3(s)

The complete ionic equation is:

Cu^2+(aq)+2Cl^-(aq)+2Na^+(aq)+CO_3^2^-(aq)->2Cl^-(aq)+2Na^+(aq)+CuCO_3(s)\\

The net ionic equation is obtained from the complete ionic equation after removing the spectator ions:

Cu^2^+(aq)+CO_3^2^-(aq)->CuCO_3(s)

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What mass of barium sulfate (233 g/mol) is produced when 125 mL of a 0.150 M solution of barium chloride is mixed with 125 mL of
Rzqust [24]

Answer:

4.37 g of barium sulphate

Explanation:

The reaction equation is;

3BaCl2(aq) + Fe2(SO4)3(aq) ---->3 BaSO4(s) + 2FeCl3(aq)

From the question, the number of moles of both barium chloride and FeSO4 = 125/1000 L × 0.150 M = 0.01875 moles

To find the limiting reactant;

3 moles of barium chloride yields 3 moles of barium sulphate

0.01875 moles of barium chloride yields 3 × 0.01875 moles/3 = 0.01875 moles of barium sulphate

1 mole of iron III sulphate yields 3 moles of barium sulphate

0.01875 molesof iron III sulphate yields 0.01875 moles ×3/1 = 0.05625 moles of barium sulphate

Hence,barium chloride is the limiting reactant

Amount of barium sulphate produced = 0.01875 moles × 233 g/mol = 4.37 g of barium sulphate

4 0
3 years ago
Which is an example of ionization?
strojnjashka [21]
Answer: SO₂ + H₂O → HSO₃ ⁻ + H⁺

Justification:

1) Ionization means formation of ions.

2) Ions are species that are not neutral, they are charged, in virtue of having less or more electrons than protons.

3) Ionization may happen in different environments.

4) Ionic compunds, like Mg(OH)₂ dissociate into ions (ionize) in water. That is the example shown in the fourth option:

Mg(OH)₂ → Mg ²⁺ + 2OH⁻

5) How much a ionic compound dissociates in water (ionize) depends on the Ksp (product solubility constant) which measures the concentrations of the ions that can be in the solution.


6) The Ksp for Mg(OH)₂ is very low, meaning that it will slightly ionize.

7) SO₂ + H₂O forms H₂SO₄, which is a strong acid, meaning that it will ionize fully in water, into the ions HSO₃ ⁻ and H⁺, so the third option is a good example of ionization.

8 0
3 years ago
How many particles are present in this diagram?
AVprozaik [17]
There are 9 particles
5 0
3 years ago
Read 2 more answers
Q#5 Balance and list the coefficients from reactants to products.
skad [1K]

A. 2Fe_2O_3(s) +3C(s) → 4Fe(s) + 3CO_2(g)

B. 2Al(s) + 3FeO(s) → Fe(s) + 3Al_2O_3(s)

C. 2Al(s) +3H_2SO_4(aq) → Al_2(SO_4)_3(aq) + 3H_2(g)

What is a balanced chemical equation?

An equation that has an equal number of atoms of each element on both sides of the equation is called a balanced chemical equation.

A. 2Fe_2O_3(s) +3C(s) → 4Fe(s) + 3CO_2(g)

B. 2Al(s) + 3FeO(s) → Fe(s) + 3Al_2O_3(s)

C. 2Al(s) +3H_2SO_4(aq) → Al_2(SO_4)_3(aq) + 3H_2(g)

Learn more about the balanced chemical equation here:

brainly.com/question/15052184

#SPJ1

8 0
2 years ago
Read 2 more answers
Explain how you would decide which represents a greater mass: 3.25 x 1022 atoms of Ca or 2.45 grams of Mg?
elena55 [62]

Answer:

  • <u>You need to convert the number of atoms of Ca into mass in grams, using Avogadro's number and the atomic mass of Ca.</u>

Explanation:

The amount of matter is measured in grams. Thus, you need to convert the number of atoms of Ca (calcium) into mass to compare with 2.45 grams of Mg.

To convert the atoms of calcium into mass, you divide by Avogadro's number, to obtain the number of moles of atoms, and then divide by the atomic mass of calcium.

<u />

<u>1. Number of moles, n</u>

      n=\dfrac{\text{number of atoms}}{\text{Avogadro's number}}\\ \\ \\ n=\dfrac{3.25\times 10^{22}}{6.022\times 10^{23}}=0.053969mol

<u />

<u>2. Mass</u>

  • mass = number of moles × atomic mass
  • mass = 0.053969mol × 40.078g/mol = 2.16g

Then, 2.45 g of Mg represent a greaer mass than the 3.25 × 10²² atoms of Ca.

4 0
3 years ago
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