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Alik [6]
3 years ago
7

se the model for projectile motion, assuming there is no air resistance and g = 32 feet per second per second. A baseball, hit 3

feet above the ground, leaves the bat at an angle of 45° and is caught by an outfielder 3 feet above the ground and 300 feet from home plate. What is the initial speed of the ball, and how high does it rise?
Physics
1 answer:
guajiro [1.7K]3 years ago
8 0

Answer:

b

Explanation:

just took the test

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A cannonball is launched with initial velocity of magnitude v0 over a horizontal surface. At what minimum angle
melisa1 [442]

Answer:

A)   θmin= 76°.

Explanation:

Given that

Speed of cannonball = Vo

Lets take θ is the angle measure from horizontal

We know that

Range R

R=\dfrac{V_o^2sin2\theta }{g}

Height h

h=\dfrac{V_o^2sin^2\theta }{2g}

Given that h should be larger than R

         h > R

\dfrac{V_o^2sin^2\theta }{2g}>\dfrac{V_o^2sin2\theta }{g}

{sin^2\theta }>2{sin2\theta }

{sin^2\theta }>4{sin\theta\ cos\theta  }

{tan\theta }>4

        θ  >75.96°

So minimum angle should be 75.96° or 76°.

4 0
3 years ago
PLEASE HELP!!
Blizzard [7]
Wind blows, and water flows, from higher pressure to lower pressure.
5 0
3 years ago
Read 2 more answers
A particle moving along the x-axis has a position given by x = (24t – 2.0t 3 ) m, where t is measured in s. What is the magnitud
Vitek1552 [10]
<h2>The magnitude 24 (\dfrac{m}{s^2} ) of the acceleration of the particle when the particle is not moving.</h2>

Explanation:

Given,

A particle moving along the x-axis has a position given by

x=(24t-2.0t^3) m      ........ (1)

To find, the magnitude (\dfrac{m}{s^2} ) of the acceleration of the particle when the particle is not moving = ?

Differentiating equation (1) w.r.t, 't', we get

\dfrac{dx}{dt} =\dfrac{d((24t-2.0t^3))}{dt}

⇒ \dfrac{dx}{dt} =24(1)-3(2.0)t^{2} =24-6t^{2}     ....... (2)

⇒ 24-6t^{2} = 0

⇒ t^{2}=2^{2}

⇒ t = 2 s

Again, differentiating equation (2) w.r.t, 't', we get

\dfrac{d^2x}{dt^2} =-12t

Put t = 2, we get

\dfrac{d^2x}{dt^2} =-12(2)=24

Thus, the magnitude 24 (\dfrac{m}{s^2} ) of the acceleration of the particle when the particle is not moving.

3 0
3 years ago
Convert 0.000238 m to cm
enot [183]

Answer:

0.0238 centimetre

Explanation:

multiply the length value by 100

3 0
3 years ago
An 97 kg climber climbs to the top of Mount Everest, which has a peak height of 8850 m above sea level. What is the climber’s po
Kisachek [45]
Eg=mgh
Eg=(97)(9.8)(8850)
Eg=8412810J
4 0
3 years ago
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