Answer:
a. 4.5secs
Explanation:
From the question, the equation describing the height is given by

at the point when the rock hit the ground, the height,h will be zero.
Hence we can have

hence the rock will hit the ground in 4.5secs
Answer:
The speed of the block when it is 5.00 m from the top of the incline is 3.04 m/s
Explanation:
given information:
s = 7.80 m
v = 3.8 m/s
if s = 5 m, v?
first we have to find the acceleration of the block using the following equation:
v² = v₀² + 2as, v₀² = 0 thus
3.8² = 2 a 7.8
a = 0.93
so, if s = 5m the final speed is
v² = 2 (0.93) (5)
= 9.26
v = √9.26
= 3.04 m/s
Answer:
3,237.78N
Explanation:
According to Newton's second law of motion
F = mass * acceleration
Since a = v-u/t
F = m(v-u)/t
Given
Mass m = 0.155kg
v = 50.0m/s
u = -44.0m/s
Time t = 0.00450secs
Substitute
F = 0.155(50-(-44))/0.00450
F = 0.155(50+44)/0.00450
F = 0.155(94)/0.00450
F = 14.57/0.00450
F = 3,237.78N
hence he hit the baseball with a force of 3,237.78N
Answer:
The gas pressure is: 1.55 atm.
Explanation:
We need to use the equation that relate the variables given at the exercise (pressure, temperature and volume) from the ideal gas law formula, when the mass is constant we can reduce the expretion
to
solving to P2 we get:
replace the values
.