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Alik [6]
3 years ago
7

se the model for projectile motion, assuming there is no air resistance and g = 32 feet per second per second. A baseball, hit 3

feet above the ground, leaves the bat at an angle of 45° and is caught by an outfielder 3 feet above the ground and 300 feet from home plate. What is the initial speed of the ball, and how high does it rise?
Physics
1 answer:
guajiro [1.7K]3 years ago
8 0

Answer:

b

Explanation:

just took the test

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The higher the amplitude of the wave, the greater its intensity and the greater its loudness.
lyudmila [28]
True,when you turn the volume up on your  television , you're actually turning up the amplitude<span>!

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4 0
3 years ago
Two metal balls have charges of 7.1 × 10-6 coulombs and 6.9 × 10-6 coulombs. They are 5.7 × 10-1 meters apart. What is the force
Zinaida [17]
Hey there, Your answer wold be 1.36 newtons rounded to 1.4 newton. This is how!

force = k (q1 * q2) / r^2 

<span>= (9.0 × 10^9 Nm^2/C^2) [(7.1 × 10^-6 C) (6.9 × 10^-6 C)] / (5.7 × 10^-1 m)^2 
</span>
<span>= [ 9.0 × 7.1 × 6.9 / (5.7)^2 ] × 10^-1 N 
</span>
<span>= 13.6 × 10^-1 N 
</span>
<span>= 1.36 N
</span>
ANSWER-1.4 


HOPE I HELPED!!!!!!!!!!
6 0
3 years ago
Read 2 more answers
The efforts of one good worker can often motivate others to reach their potential through a process called A. Modeling B. Mentor
olganol [36]
It would be A. Modeling.
4 0
3 years ago
Read 2 more answers
A mass of gas occupies 20 cm3 at 5 degrees Celcius and 760 mm Hg pressure. What is its volume at 30 degrees Celcius and 800 mm H
suter [353]

Answer:

20.7 cm³

Explanation:

From the question given above, the following data were obtained:

Initial volume (V1) = 20 cm³

Initial temperature (T1) = 5 °C

Initial pressure (P1) = 760 mm Hg

Final temperature (T2) = 30 °C

Final pressure (P2) = 800 mm Hg

Final volume (V2) =?

Next we shall convert celsius temperature to Kelvin temperature. This can be obtained as follow:

Temperature (K) = Temperature (°C) + 273

Initial temperature (T1) = 5 °C

Initial temperature (T1) = 5 °C + 273 = 278 K.

Final temperature (T2) = 30 °C

Final temperature (T2) = 30 °C + 273 = 303 K.

Finally, we shall determine the new volume of the gas as follow:

Initial volume (V1) = 20 cm³

Initial temperature (T1) = 278 K

Initial pressure (P1) = 760 mm Hg

Final temperature (T2) = 303 K

Final pressure (P2) = 800 mm Hg

Final volume (V2) =?

P1V1/T1 = P2V2/T2

760 × 20 /278 = 800 × V2/303

Cross multiply

278 × 800 × V2 = 760 × 20 × 303

Divide both side by 278 × 800

V2 = (760 × 20 × 303) / (278 × 800)

V2 = 20.7 cm³

Therefore, the new volume of the gas is 20.7 cm³

3 0
4 years ago
Mario uses a hot plate to heat a beaker of 150mL of water. He used a
riadik2000 [5.3K]

Answer:

the point of the BOILING point DOES NOT CHANGE

         T = 100ºC

Explanation:

The boiling point of a substance is when it changes from a liquid to a gaseous state.

This point depends on the forces that join the molecules of the liquid, if we take the macroscopic variables of thermodynamics: Temperature, pressure depends on the two in a phase diagram, but nowhere is it dependent on the amount of matter.

Therefore the point of the BOILING point DOES NOT CHANGE

         T = 100ºC

8 0
3 years ago
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