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Gre4nikov [31]
3 years ago
11

PLEASE HELP ME What is the net force acting on the car?

Physics
1 answer:
Hitman42 [59]3 years ago
3 0
The net force acting on the car is 3 which slows the car down.
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A source at rest emits light of wavelength 500 nm. When it is moving at 0.90c toward an observer, the observer detects light of
Vesna [10]

Answer:

The observer detects light of wavelength is 115 nm.

(b) is correct option

Explanation:

Given that,

Wavelength of source = 500 nm

Velocity = 0.90 c

We need to calculate the wavelength of observer

Using Doppler effect

\lambda_{o}=\sqrt{\dfrac{1-\beta}{1+\beta}}\lambda_{s}

Where, \beta=\dfrac{c}{v}

\lambda_{o}=\sqrt{\dfrac{c-0.90c}{c+0.90c}}\times500\times10^{-9}

\lambda_{o}=115\ nm

Hence, The observer detects light of wavelength is 115 nm.

8 0
3 years ago
Which vehicle will have more kinetic energy, a parked<br> semitruck or a car moving at 50 km/h?
Neporo4naja [7]

Answer:

a semi truck

Explanation:

3 0
3 years ago
Suppose that you have a rod that is positively charged, a rod that is negatively charged and a stand that allows rotation. If yo
amm1812

Answer:

Explanation:

A charge is produced when an atom losses or gains an electron. The law of static electricity states that like charges repels, while unlike charges attracts.

1. To determine the charge on the polystyrene rod.

Place the polystyrene rod on the non-conducting rotating stand, and bring the positively charged rod close to it. If attraction occurs, it shows that it is oppositely charged. If repulsion occurs, it shows that it is positively charged.

Bringing a negatively charged rod close to the rotating polystyrene rod would attract it if the charge is opposite. But if the charge on the two rods are the same, repulsion occurs.

2a. When the polystyrene rod is positively charged, it would attract the negatively charged rod but repel the positively charged rod.

b. When the polystyrene rod is negatively charged, it would repel the negatively charged rod but attract the positively charged rod.

c. When the polystyrene rod is uncharged, no reaction would be observed when either the positively charged or negatively charged rod is brought close to it.

3 0
3 years ago
As engineers sketch, they take periodic ____ to verify that the design maintains the appropriate ratio for the given scale.
Karolina [17]
They take periodic time

6 0
3 years ago
Two containers have a substantial amount of the air evacuated out of them so that the pressure inside is half the pressure at se
adoni [48]

Answer:

(a)\ F_{No} = [P_{No} - \frac{P_{area}}{2}]* A

(b)\ F_{No} = 771.125N

Explanation:

Given

d_D = 6000ft ---- Altitude of container in Denver

A = 0.0155m^2 -- Surface Area of the container lid

P_D = 79000Pa --- Air pressure in Denver

P_{No} = 100250Pa --- Air pressure in New Orleans

<em>See comment for complete question</em>

Solving (a): The expression for F_{No

Force is calculated as:

F = \triangle P * A

The force in New Orleans is:

F_{No} = \triangle P * A

Since the inside pressure is half the pressure at sea level, then:

\triangle P = P_{No} - \frac{P_{area}}{2}

Where

P_{area} = 101000Pa --- Standard Pressure

Recall that:

F_{No} = \triangle P * A

This gives:

F_{No} = [P_{No} - \frac{P_{area}}{2}]* A

Solving (b): The value of F_{No

In (a), we have:

F_{No} = [P_{No} - \frac{P_{area}}{2}]* A

Where

A = 0.0155m^2

P_{No} = 100250Pa

P_{area} = 101000Pa

So, we have:

F_{No} = [100250 - \frac{101000}{2}] * 0.0155

F_{No} = [100250 - 50500] * 0.0155

F_{No} = 49750* 0.0155

F_{No} = 771.125N

4 0
3 years ago
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