Answer:
Option 2. and 3.
Explanation:
Anode heel effect or simply heel effect is observed in X-ray tubes.
It is the change in the intensity of the emitted X-rays from the anode and this intensity is direction dependent and depends on the direction of the emitted X-rays along the axis of anode-cathode.
This effect results from the absorption of X-rays prior to leaving the anode, their production source.
The absorption of photons is more in the anode heel than the toe of the anode which results in the anode heel effect.
this is a link to a web sight with a diagram to help you
https://www.google.com/url?sa=i&source=images&cd=&ved=2ahUKEwjw4v7knNDgAhVyUN8KHWgWD-wQjRx6BAgBEAU&url=%2Furl%3Fsa%3Di%26source%3Dimages%26cd%3D%26ved%3D%26url%3Dhttps%253A%252F%252Ffuturism.com%252Fwhere-do-all-the-elements-come-from%26psig%3DAOvVaw19_FOCuWs_nMsyY1YT0Da-%26ust%3D1550955269844922&psig=AOvVaw19_FOCuWs_nMsyY1YT0Da-&ust=1550955269844922
Ummm gas takes the shape and volume of its container, but I don't know about plasma. Solids definitely don't, and liquids don't change their volumes. So I would say gas. :)
The amount of work done by the student in carrying the backpack is 30.6 J
<h3>Definition of workdone </h3>
Workdone is defined as the product of force and distance moved in the direction of the force.
Work done (Wd) = Force (F) × distance (d)
Wd = Fd
Also,
Force (F) = mass (m) × acceleration (a)
F = ma
Therefore,
Wd = (ma) × d
With the above formula, we can obtain the work done by the student.
<h3>How to determine the Workdone </h3>
From the question given above, the following data were obtained:
- Mass (m) = 12 Kg
- Acceleration (a) = 0.51 m/s²
- Distance (d) = 5 m
- Workdone (Wd) =?
Wd = (ma) × d
Wd = 12 × 0.51 × 5
Wd = 30.6 J
Learn more about workdone:
brainly.com/question/14667371
Answer:
The speed of the block is 8.2 m/s
Explanation:
Given;
mass of block, m = 2.1 kg
height above the top of the spring, h = 5.5 m
First, we determine the spring constant based on the principle of conservation of potential energy
¹/₂Kx² = mg(h +x)
¹/₂K(0.25)² = 2.1 x 9.8(5.5 +0.25)
0.03125K = 118.335
K = 118.335 / 0.03125
K = 3786.72 N/m
Total energy stored in the block at rest is only potential energy given as:
E = U = mgh
U = 2.1 x 9.8 x 5.5 = 113.19 J
Work done in compressing the spring to 15.0 cm:
W = ¹/₂Kx² = ¹/₂ (3786.72)(0.15)² = 42.6 J
This is equal to elastic potential energy stored in the spring,
Then, kinetic energy of the spring is given as:
K.E = E - W
K.E = 113.19 J - 42.6 J
K.E = 70.59 J
To determine the speed of the block due to this energy:
KE = ¹/₂mv²
70.59 = ¹/₂ x 2.1 x v²
70.59 = 1.05v²
v² = 70.59 / 1.05
v² = 67.229
v = √67.229
v = 8.2 m/s
