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Vladimir [108]
4 years ago
12

Calculating heat gained or lost requires mass, specific heat , and

Physics
1 answer:
Leto [7]4 years ago
8 0
B. relative humidity
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Is gravity air resistance?
kolezko [41]

The engineering principles that this project is based upon are gravity and air resistance. Gravity and air resistance are fundamental concepts of many forms of engineering. After we demonstrate the physical principles of gravity and air resistance through various experiments, the children are to pair off into groups of 2 to apply these concepts to an activity. The demonstrations will include dropping a parachute, a small and large feather, and a maple seed and explaining how air resistance affects their movement.


Using only paper towels, paper, scotch tape, scissors and string as construction materials, the children are to brainstorm, design and create a contraption that will make a pencil or a piece of pasta, depending on their age, fall as slowly as possible. This activity is designed for children ages 6-16. The level of difficulty can be adapted with different materials and different falling objects. The older children will be given heavier objects and a limited amount of material.


By participating in this activity, the children will gain a better understanding of how gravity and air resistance affects falling objects. They will have to work cooperatively with team members in order to reach the goal. While each group tests their innovation, the others will compare their ideas to the one that is being tested and learn the strengths and weaknesses of different designs.


As part of a teachers demonstration our group constructed three parachutes with different characteristics out of nylon. One of the parachutes has one large hole in the center of it. Another parachute has several holes throughout. The third parachute has no holes in it. The idea is that the parachute with the most holes will fall the fastest, where as the one without any hole will fall the slowest, and the one with only one hole will fall between the other two. This will demonstrate how the surface area of a parachute causes the air resistance and makes objects fall slowly.


Our activity meets all of the specified requirements. The children are to solve a problem using physical principals that they have learned, thus engaging in an engineering activity. This activity appeals to all types of children; everyone loves to drop things. Components to the kit are safe, durable and do not take up much room. The activity description is very open-ended and so the children are free to design an original contraption anyway they please. The materials are all cheap and easily accessible at home and at school. Given the time it will take for children to brainstorm ideas, design, construct and test a device, it will take the full length of a class period. The whole kit will fit in a plastic storage tub easily because none of the objects in the kit are longer than one foot.

<span>Discovering Gravity & Air ResistanceBy Jason, Allison, and Dave</span><span> <span>If two objects, an elephant and a feather, are dropped off of the side of a building, which would experience a greater force of air resistance during the fall? Which would hit the ground first?<span>  Note: The above graphic requires Flash.</span>If two balls, one made of foam, and one made of metal, are dropped simultaneously from a tall building, which will fall the fastest?</span></span> <span> <span>What's included in the kit:(1) Teachers Manual(3) Demo Parachutes(1) Roll of Paper Towels(1) Pack of Pencils (24)(1) Spool of string(2) Rolls of Scotch Tape(10) Pairs of Safety Scissors(100) Sheets of Paper(1) Box of Paper Clips(1) Box of Pasta(2) Large Feathers(2) Small Feathers(2) Toy Parachutes   </span></span>

7 0
4 years ago
A car of mass m=1000kg is traveling at speed v and brakes. The skid marks are 20m long and the coefficient of kinetic friction i
scoray [572]

Answer:

v = 14 m/s

  = 31.3 mph

The answer would be the same if the mass of the car were 2000 kg

Explanation:

Let V be the final velocity of the car after skidding, and v be the initial velocity of the car. Let a be the acceleration of the car and Δx be the distance the car travels after applying brakes (length of the skid marks). Let Fk be the force of friction between the tyres and the road. Let N be the normal force exerted on the car and μ be the co efficient of kinetic friction.

V^2 = v^2 + 2×a×Δx

Now V, the final velocity is zero as the car stops

0 = v^2 + 2×a×Δx

v^2 = -2×a×Δx

v =√-2×a×Δx    .....*

Now applying Newton's Second Law

Fnet = m×a

-Fk = m×a

-μ×N = m×a

-μ×m×g = m×a (The mass cancels out)

a =  -μ×g

Substituting the value of a back to equation *

v = √-2×(-μ×g)×Δx  

v = √-2×(-0.5×9.8)×20

v = 14 m/s

Therefore the speed the car was travelling with v = 14 m/s

which is equal to 31.3 mph

Now if you were to change the mass of the car to 2000 kg the value for v would still be the same. As it is seen above mass cancels out so it does not influence or affect the value of the velocity obtained.

8 0
3 years ago
Jana filled a cup with water. She put the cup in the sunlight and checked the temperature every 30 minutes. After 90 minutes, sh
Virty [35]
The correct answer will be C
6 0
3 years ago
Read 2 more answers
A man is standing on the edge of a 20.0 m high cliff. He throws a rock horizontally with an initial velocity of 10.0 m/s.
kherson [118]

Answer:

<em>a. The rock takes 2.02 seconds to hit the ground</em>

<em>b. The rock lands at 20,2 m from the base of the cliff</em>

Explanation:

Horizontal motion occurs when an object is thrown horizontally with an initial speed v from a height h above the ground. When it happens, the object moves through a curved path determined by gravity until it hits the ground.

The time taken by the object to hit the ground is calculated by:

\displaystyle t=\sqrt{\frac{2h}{g}}

The range is defined as the maximum horizontal distance traveled by the object and it can be calculated as follows:

\displaystyle d=v.t

The man is standing on the edge of the h=20 m cliff and throws a rock with a horizontal speed of v=10 m/s.

a,

The time taken by the rock to reach the ground is:

\displaystyle t=\sqrt{\frac{2*20}{9.8}}

\displaystyle t=\sqrt{4.0816}

t = 2.02 s

The rock takes 2.02 seconds to hit the ground

b.

The range is calculated now:

\displaystyle d=10\cdot 2.02

d = 20.2 m

The rock lands at 20,2 m from the base of the cliff

5 0
3 years ago
Help me please (* ̄(エ) ̄*)​
Len [333]

Answer:

1) Are always conservative

Explanation:

Elastic forces are always conservative.

Hope it helps you.

please mark as the brainliest answer.

3 0
3 years ago
Read 2 more answers
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