Question

Find whole number values for h and the length of the missing shorter base.

Answer 1

The area of a shape is the amount of space the shape can occupy.

The values of the height and the shorter base are: 8cm and 2cm respectively

The given dimensions are:

$\mathbf{Area = 40cm^2}$

$\mathbf{Base = 8cm}$

The area of a trapezoid (see attachment) is:

$\mathbf{Area = \frac 12(Base_1 + Base_2) \times Height}$

So, we have:

$\mathbf{40 = \frac 12(8 + Base_2) \times Height}$

Multiply through by 2

$\mathbf{80 = (8 + Base_2) \times Height}$

The whole number values of base and height that satisfy the above equation is:

$\mathbf{Base_2 = 2}$

$\mathbf{Height = 8}$

i.e.

$\mathbf{80 = (8 + Base_2) \times Height}$

$\mathbf{80 = (8 + 2) \times 8}$

$\mathbf{80 = 10 \times 8}$

$\mathbf{80 = 80}$

Hence, the values of the height and the shorter base are: 8cm and 2cm respectively

Read more about areas at:

brainly.com/question/16418397